Chapter 12: Problem 20
a. Find the exact value of \(\cos 315^{\circ}\) by using \(\cos \left(270^{\circ}+45^{\circ}\right) .\) b. Find the exact value of \(\sin 315^{\circ}\) by using \(\cos ^{2} \theta+\sin ^{2} \theta=1\) and the value of \(\cos 315^{\circ}\) found in a. c. Find the exact value of \(\cos 345^{\circ}\) by using \(\cos \left(315^{\circ}+30^{\circ}\right) .\) d. Explain why \(\cos 405^{\circ}=\cos 45^{\circ}\)
Short Answer
Step by step solution
Use the Cosine Addition Formula for 315°
Use Pythagorean Identity to Find \( \sin 315^{\circ} \)
Use Cosine Addition Formula for 345°
Explain Why \( \cos 405^{\circ} = \cos 45^{\circ} \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Addition Formula
- \( \cos(\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta \)
- \( \cos 315^{\circ} = \cos 270^{\circ} \cos 45^{\circ} - \sin 270^{\circ} \sin 45^{\circ} \)
- = \( 0 \times \frac{\sqrt{2}}{2} - (-1) \times \frac{\sqrt{2}}{2} \)
- = \( \frac{\sqrt{2}}{2} \)
Pythagorean Identity
- \( \cos^2 \theta + \sin^2 \theta = 1 \)
- \( \left(\frac{\sqrt{2}}{2}\right)^2 + \sin^2 315^{\circ} = 1 \)
- \( \frac{2}{4} + \sin^2 315^{\circ} = 1 \)
- \( \frac{1}{2} + \sin^2 315^{\circ} = 1 \)
- \( \sin^2 315^{\circ} = \frac{1}{2} \)
- \( \sin 315^{\circ} = -\frac{\sqrt{2}}{2} \) \(\text{(since 315° is in the fourth quadrant where sine is negative)}\)
Angle Reduction
- Given \( \theta = 405^{\circ} \), the reduction is \( \theta - 360^{\circ} = 45^{\circ} \)
- Thus, \( \cos 405^{\circ} = \cos 45^{\circ} \)
Special Angles
- \( \cos 45^{\circ} = \sin 45^{\circ} = \frac{\sqrt{2}}{2} \)
- \( \cos 30^{\circ} = \frac{\sqrt{3}}{2}, \; \sin 30^{\circ} = \frac{1}{2} \)
- \( \cos 60^{\circ} = \frac{1}{2}, \; \sin 60^{\circ} = \frac{\sqrt{3}}{2} \)
- \( \cos 345^{\circ} = \frac{\sqrt{6} + \sqrt{2}}{4} \)