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Maggie said that \(\cos (A+B)+\cos (A-B)=\cos 2 A .\) Do you agree with Maggie? Justify your answer.

Short Answer

Expert verified
Maggie's statement is incorrect for arbitrary angles \( A \) and \( B \).

Step by step solution

01

Use Sum-to-Product Formulas

First, apply the sum-to-product identities, which state that for any angles \( x \) and \( y \), \( \cos x + \cos y = 2 \cos \left( \frac{x+y}{2} \right) \cos \left( \frac{x-y}{2} \right) \). For the given expression, set \( x = A + B \) and \( y = A - B \).
02

Apply the Formula to the Expression

Use the fact that \( \cos(A + B) + \cos(A - B) = 2 \cos \left( \frac{(A+B)+(A-B)}{2} \right) \cos \left( \frac{(A+B)-(A-B)}{2} \right) \). Simplify inside the fractions:\[\cos(A+B) + \cos(A-B) = 2 \cos(A) \cos(B)\]
03

Compare with \( \cos(2A) \)

We know that \( \cos(2A) = \cos^2(A) - \sin^2(A) \), which can be rewritten using the double angle identity as \( \cos(2A) = 2 \cos^2(A) - 1 \). Compare this with \( 2 \cos(A) \cos(B) \), which is not equivalent unless very specific conditions are met, such as \( B \) being \( 0 \) or integer multiples of \( 2\pi \).
04

Conclusion

Finally, since the expressions \( 2 \cos(A) \cos(B) \) and \( \cos(2A) \) are generally not equal for arbitrary \( A \) and \( B \), Maggie's statement is incorrect unless specific conditions hold.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sum-to-Product Formulas
The Sum-to-Product Formulas are essential tools in trigonometry that help convert the sum or difference of trigonometric functions into a product. This transformation simplifies complex expressions and is useful in various applications such as integration or solving equations. Consider the sum of cosines: \[\cos x + \cos y = 2 \cos \left( \frac{x+y}{2} \right) \cos \left( \frac{x-y}{2} \right).\] This formula takes two cosine values and represents them as a product of cosines, using averages and differences of angles.

In the original exercise, we set \(x = A + B\) and \(y = A - B\), and applied this identity. By inputting these values into the sum-to-product formula, we converted the sum of cosines, \(\cos(A + B) + \cos(A - B)\), into a product: \[2 \cos(A) \cos(B).\]This form is much easier to handle and compare to other trigonometric expressions, such as those in double angle identities.
Double Angle Identity
The Double Angle Identity is another foundational concept in trigonometry, providing a means to express trigonometric functions of double angles \((2A)\) in terms of single angles \((A)\). For cosine, this identity is expressed as: \[\cos(2A) = \cos^2(A) - \sin^2(A).\] This can also be rewritten using the Pythagorean identity \(\sin^2(A) + \cos^2(A) = 1\), giving us:\[\cos(2A) = 2\cos^2(A) - 1.\]It's important to note that the double angle identity represents the change in trigonometric values as the angle is doubled. In Maggie's situation, the goal was to compare \(\cos(2A)\) with \(2 \cos(A) \cos(B)\). Unfortunately, these are not equivalent unless specific conditions (like \(B = 0\)) are met. The double angle identity can thus demonstrate discrepancies in Maggie's statement when \(B\) varies from these special conditions.
Cosine Addition and Subtraction Formulas
Cosine Addition and Subtraction Formulas are crucial for computing the cosine of the sum or difference of two angles, which aren't directly given by a trigonometric circle. The identities are:- For sums: \(\cos(A + B) = \cos(A)\cos(B) - \sin(A)\sin(B)\)- For differences: \(\cos(A - B) = \cos(A)\cos(B) + \sin(A)\sin(B)\)These formulas help in breaking down complex expressions into simpler components of single angles. In the initial exercise, these formulas were implied in the manipulation and simplification of the expression \(\cos(A + B) + \cos(A - B)\). By writing it out using the sum-to-product formula, the resulting forms of each term confirmed the distinct characteristics from the double angle identity for arbitrary \(A\) and \(B\). The addition and subtraction formulas facilitate deeper insights into the relationships between angles, revealing the nature of trigonometric expressions beyond basic calculations.

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Most popular questions from this chapter

a. Find the exact value of \(\sin 210^{\circ}\) by using \(\sin \left(270^{\circ}-60^{\circ}\right)\) b. Find the exact value of \(\cos 210^{\circ}\) by using \(\cos \left(270^{\circ}-60^{\circ}\right)\) c. Find the exact value of \(\sin 165^{\circ}\) by using \(\sin \left(210^{\circ}-45^{\circ}\right)\) d. Use the value of \(\sin 165^{\circ}\) found in \(c\) to find \(\sin \left(-15^{\circ}\right)\) by using \(\sin \left(165^{\circ}-180^{\circ}\right) .\) e. Use the value of \(\sin \left(-15^{\circ}\right)\) found in \(d\) to find \(\sin 195^{\circ}\) by using \(\sin \left(180^{\circ}-\left(-15^{\circ}\right)\right)\) I. Use the value of \(\sin \left(-15^{\circ}\right)\) found in \(\mathrm{d}\) to find the exact value of \(\sin 105^{\circ} .\)

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An engineer wants to determine \(C D\) , the exact height of a building. To do this, he first locates \(B\) on \(\overline{C D}\) , a point 30 feet above \(C\) at the foot of the building. Then he locates \(A,\) a point on the ground 40 feet from \(C\) . From \(A\) , the engineer then finds that the angle of elevation of \(D\) is \(45^{\circ}\) larger than \(\theta\) , the angle of elevation of \(B .\) a. Find \(A B, \sin \theta,\) and \(\cos \theta\) b. Use \(\sin \theta\) and \(\cos \theta\) found in a to find the exact value of \(\cos \left(\theta+45^{\circ}\right) .\) c. Use the value of \(\cos \left(\theta+45^{\circ}\right)\) found in \(\mathbf{b}\) to find \(A D .\) d. Find \(C D,\) the height of the building.

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