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Is arctan \(1=220^{\circ}\) a true statement? Justify your answer. \(y=\arcsin \left(-\frac{\sqrt{3}}{2}\right)\)

Short Answer

Expert verified
No, it's false: \(\arctan(1) = 45^\circ \), not \(220^\circ\). \(y = -60^\circ\).

Step by step solution

01

Understanding Arctan Function

The arctangent function, denoted as \( \arctan \), represents the angle whose tangent is a specific value. It is important to recognize that the range of the arctangent function is \((-\frac{\pi}{2}, \frac{\pi}{2})\) in radians, or approximately \((-90^\circ, 90^\circ)\).
02

Evaluation of arctan(1)

To determine \( \arctan(1) \), note that the tangent of which angle equals 1. The tangent of \(45^\circ \) (or \(\frac{\pi}{4}\) radians) is 1. Therefore, \(\arctan(1) = 45^\circ\).
03

Comparison with 220°

Since the arctan function's range is \((-90^\circ, 90^\circ)\), and we've established that \(\arctan(1) = 45^\circ\), it cannot be equal to \(220^\circ\). Thus, the statement is false.
04

Understanding Arcsin Function

The arcsine function, denoted as \( \arcsin \), is the inverse of the sine function and has a range of \([-\frac{\pi}{2}, \frac{\pi}{2}]\) or approximately \([-90^\circ, 90^\circ]\).
05

Evaluation of arcsin \(-\frac{\sqrt{3}}{2}\)

The sine of an angle \(-60^\circ\) (or \(-\frac{\pi}{3}\) radians) yields \(-\frac{\sqrt{3}}{2}\). Thus, \(y = \arcsin\left(-\frac{\sqrt{3}}{2}\right) = -60^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arctan Function
The arctan function, often represented as \( \arctan \), is the inverse of the tangent function. It finds the angle whose tangent value equals a specific number. For any given number \(x\), \( \arctan(x) \) provides the angle \( \theta \) such that \( \tan(\theta) = x \).

This function is widely used in trigonometry to determine angles based solely on their tangent values. What's important to remember is that the range of the arctan function is \((-\frac{\pi}{2}, \frac{\pi}{2})\) when measured in radians, which translates to \((-90^\circ, 90^\circ)\) in degrees.
  • This narrow range ensures that the \( \arctan \) function provides a unique angle for every real number \(x\).
  • Note that this aspect is crucial for applications like angle evaluation and solving trigonometric equations.
Given this range, the angle returned by the \( \arctan \) function will always fall between \(-90^\circ \) and \(+90^\circ\). Hence, any claim that \( \arctan(1) \) equals \(220^\circ\) is false because \(220^\circ\) falls outside of this range.
Arcsin Function
The arcsin function, written as \(\arcsin \), is the inverse of the sine function. It helps to find the angle whose sine is a given number. If you have a value \(y\), \(\arcsin(y)\) gives you the angle \(\theta\) such that \(\sin(\theta) = y\).

The range for the arcsin function is \([-\frac{\pi}{2}, \frac{\pi}{2}]\), or -90° to 90° in degrees. This implies that any result from the \(\arcsin\) function will be within these bounds. This characteristic is important to ensure the uniqueness of the output angle.
  • For example, the function \(\arcsin(-\frac{\sqrt{3}}{2})\) results in \(-60^\circ\).
  • This outcome is valid because \(-60^\circ \) lies within the arcsin range.
Whenever you find yourself evaluating inverse sine, the range should be the first thing you consider, as it dictates the set of possible angle outputs.
Range of Inverse Trigonometric Functions
The concept of range is pivotal in understanding inverse trigonometric functions. It essentially limits the output values of these functions to specific intervals, ensuring that for each input, there is only one valid output.

These ranges are:
  • \(\arctan\): \((-\frac{\pi}{2}, \frac{\pi}{2})\) or \((-90^\circ, 90^\circ)\)
  • \(\arcsin\): \([-\frac{\pi}{2}, \frac{\pi}{2}]\) or \([-90^\circ, 90^\circ]\)
This concept of range guarantees that the inverse functions do not produce ambiguous results. Without these ranges, the same inverse function could potentially output multiple angles for a single input value, leading to confusion.

In real-world applications, understanding these ranges helps one correctly interpret the results provided by inverse trigonometric calculations. Always keep these boundaries in mind when solving problems to ensure the angles you find are meaningful and correct.
Angle Evaluation
Angle evaluation involves determining the precise angle that corresponds to a given trigonometric value, using the inverse trigonometric functions like \(\arcsin\) and \(\arctan\). When evaluating angles, it is crucial to adhere to the defined ranges of these inverse functions.

For instance, if you're tasked with finding \(\arctan(1)\), you know the resulting angle must be within \((-90^\circ, 90^\circ)\). Thus, \(\arctan(1)\) results in \(45^\circ\), as this is the only angle within the arctangent range where \(\tan(45^\circ) = 1\).
  • Similarly, angle evaluation also helps with determining sine-related angles using \(\arcsin\).
  • When attempting \(\arcsin(-\frac{\sqrt{3}}{2})\), knowing that the angle must be between \(-90^\circ \) and \(+90^\circ\) leads to the conclusion of \(-60^\circ\).
Thorough understanding of angle evaluation not only makes solving inverse trigonometric problems easier but also ensures accuracy in real-life calculations and scenarios.

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Most popular questions from this chapter

Sketch one cycle of each function. \(y=3 \cos x\)

Recall from your geometry course that a polygon is circumscribed about a circle if each side of the polygon is tangent to the circle. Since each side is tangent to the circle, the radius of the circle is perpendicular to each side at the point of tangency. We will use the tangent tunction to examine the formula for the perimeter of a circumscribed regular polygon. Let square \(A B C D\) be circumscribed about circle \(O .\) A radius of the circle, \(\overline{O P},\) is perpendicular to \(\overline{A B}\) at \(P .\) (1) In radians, what is the measure of \(\angle A O B ?\) (2) Let \(m \angle A O P=\theta .\) If \(\theta\) is equal to one-half the measure of \(\angle A O B\) , find \(\theta .\) (3) Write an expression for \(A P\) in terms of \(\tan \theta\) and \(r,\) the radius of the circle. (4) Write an expression for \(A B=s\) in terms of \(\tan \theta\) and \(r\) (5) Use part \((4)\) to write an expression for the perimeter in terms of \(r\) and the number of sides, \(n\) . b. Let regular pentagon \(A B C D E\) be circumscribed about circle \(O .\) Repeat part a using pentagon \(A B C D E .\) c. Do you see a pattern in the formulas for the perimeter of the square and of the pentagon? If so, make a conjecture for the formula for the perimeter of a circumscribed regular polygon in terms of the radius \(r\) and the number of sides \(n .\)

Sketch one cycle of each function. \(y=\sin \left(x+\frac{\pi}{2}\right)\)

a. Sketch the graphs of \(y=\tan x\) and \(y=\cot x\) for \(-\pi \leq x \leq \pi\) b. Name four values of \(x\) in the interval \(-\pi \leq x \leq \pi\) for which tan \(x=\cot x\)

Using the graphs of each function, determine whether each function is even, odd, or neither. a. \(y=\tan x\) b. \(y=\csc x\) c. \(y=\sec x\) d. \(y=\cot x\)

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