Chapter 6: Problem 14
Factor each expression. $$ 125 x^{3}-27 $$
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Chapter 6: Problem 14
Factor each expression. $$ 125 x^{3}-27 $$
These are the key concepts you need to understand to accurately answer the question.
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Simplify each expression. $$ \frac{7 !}{3 !(7-3) !} $$
In the sequence \(1 !, 2 !, 3 !, 4 !, 5 !, 6 !, \ldots,\) the first term that ends with a zero is \(5 ! .\) a. Explain why \(5 !\) and all the terms following \(5 !\) end with a zero. b. Find the number of zeros with which \(100 !\) ends.
Find the specified term of each binomial expansion. Fourth term of \((x+2)^{5}\)
Expand each binomial. $$ (2 x+3 y)^{4} $$
What is the expanded form of \((a-b)^{3} ?\) \(\begin{array}{ll}{\text { A. } a^{3}+a^{2} b+a b^{2}+b^{3}} & {\text { B. } a^{3}+3 a^{2} b+3 a b^{2}+b^{3}} \\ {\text { C. } a^{3}-a^{2} b+a b^{2}-b^{3}} & {\text { D. } a^{3}-3 a^{2} b+3 a b^{2}-b^{3}}\end{array}\)
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