Chapter 14: Problem 47
Simplify each expression. $$ \sin ^{2} \frac{\theta}{2}-\cos ^{2} \frac{\theta}{2} $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 14: Problem 47
Simplify each expression. $$ \sin ^{2} \frac{\theta}{2}-\cos ^{2} \frac{\theta}{2} $$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Geometry The lengths of the adjacent sides of a parallelogram are 54 \(\mathrm{cm}\) and 78 \(\mathrm{cm}\) . The larger angle measures \(110^{\circ} .\) What is the length of the longer diagonal? Round your answer to the nearest centimeter.
Which expression is equal to \(\cos 50^{\circ} ?\) A. \(\sin 20^{\circ} \cos 30^{\circ}+\cos 20^{\circ} \sin 30^{\circ} \quad\) B. \(\sin 20^{\circ} \cos 30^{\circ}-\cos 20^{\circ}-\cos 20^{\circ} \sin 30^{\circ}\) \(\mathrm{C} \cdot \cos 20^{\circ} \cos 30^{\circ}+\sin 20^{\circ} \sin 30^{\circ} \quad\) D. \(\cos 20^{\circ} \cos 30^{\circ}-\sin 20^{\circ} \sin 30^{\circ}\)
Use a half-angle identity to find the exact value of each expression. $$ \cos 15^{\circ} $$
Use a double-angle identity to find the exact value of each expression. $$ \tan 240^{\circ} $$
In \(\triangle A B C, a=20 \mathrm{m}, b=14 \mathrm{m},\) and \(c=16 \mathrm{m} .\) Find \(m \angle A\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.