Chapter 10: Problem 40
Find the vertices and the asymptotes of each hyperbola. $$ y^{2}-x^{2}=1 $$
Short Answer
Expert verified
The vertices of the hyperbola are at (0, 1) and (0, -1), and the asymptotes are given by the equations y = x and y = -x.
Step by step solution
01
Identify the center, a, and b
By comparing the given equation \(y^{2} - x^{2} = 1\) with the standard equation of a hyperbola \(\frac{(y-K)^{2}}{a^{2}} - \frac{(x-H)^{2}}{b^{2}} = 1\), we can see that the center (H, K) is at the origin (0, 0) because the terms for H and K are missing. This is also a case where a and b are both 1.
02
Determine the vertices
The vertices of the hyperbola are found by moving 'a' units vertically from the center since the y term is first in the equation. So, the vertices are at (0, 1) and (0, -1).
03
Find the asymptotes
For a hyperbola centered at (H, K) with equation \(\frac{(y-K)^{2}}{a^{2}} - \frac{(x-H)^{2}}{b^{2}} = 1\), the asymptotes are \(y = K \pm \frac{a}{b}(x - H)\). In this case, since the center is at the origin and a and b are both 1, the equations of the asymptotes are y = x and y = -x.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Asymptotes in a Hyperbola
Asymptotes in a hyperbola are straight lines that the curve approaches but never touches. They provide a framework that guides the shape of the hyperbola. Asymptotes give us an idea about the steepness and orientation of the hyperbola's branches.
- They are significant in understanding the hyperbola's growth pattern.
- For a hyperbola centered at (H, K), the general formula for asymptotes is: \( y = K \pm \frac{a}{b}(x - H) \)
- In the equation \( y^2 - x^2 = 1 \), the center is at the origin (0, 0). Thus, H and K are zero.
- With a and b equal to 1, the asymptotes of this hyperbola are \( y = x \) and \( y = -x \).
Locating the Vertices of a Hyperbola
Vertices are the points where the hyperbola changes direction. They are crucial in grasping the hyperbola's geometric structure and are directly tied to its center.
- To determine vertices, identify the center of the hyperbola and measure 'a' units from it.
- For the equation \( y^2 - x^2 = 1 \), there's no transformation affecting the center, meaning it stays at \( (0, 0) \).
- Given that 'a' is 1 in \( y^2 - x^2 = 1 \), you move 1 unit from the center along the y-axis.
- The vertices, therefore, are at the points \( (0, 1) \) and \( (0, -1) \).
The Standard Form of a Hyperbola
The standard form of a hyperbola is a crucial representation, allowing us to easily identify key characteristics. It sets the stage for locating the center, vertices, and asymptotes. Depending on the orientation, the standard form is slightly different.
- When the y-term comes before the x-term in subtraction, the hyperbola opens vertically; hence the form is: \( \frac{(y-K)^2}{a^2} - \frac{(x-H)^2}{b^2} = 1 \)
- If it's the reverse, with the x-term first, the hyperbola opens horizontally.
- Here, like in our problem \( y^2 - x^2 = 1 \), the y-term comes first, indicating a vertical opening.
Identifying the Center of a Hyperbola
The center of a hyperbola is its balancing point. When you understand the center's position, the rest of the hyperbola's attributes align easily around it.
- In transforming a standard equation, the center \( (H, K) \) is indicated by its differences from the y and x terms.
- For \( y^2 - x^2 = 1 \), there are no H or K values suggested, which means the center is at \( (0, 0) \).
- If the equation had terms like \((y - 2)^2\) or \((x + 3)^2\), the center would shift to \( (2, -3) \).