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Problem 60

Solve each absolute value inequality. \(|3 x-5|-2>0\)

Problem 61

Match the property name with the appropriate equation. Opposite of a Product $$ \begin{array}{l}{\text { A. } 2(s-t)=2 s-2 t} \\ {\text { B. }-(a-b)=(-1)(a-b)} \\ {\text { C. }(7-y) \div(2 y)=\frac{7-y}{2 y}} \\\ {\text { D. }-[-(x-10)]=x-10} \\ {\text { E. }-(2 t-10)=11-2 t} \\ {\text { F. }-11=2 t+(-11)} \\ {\text { H. }-[3+(-y)]=-3+[-(-y)]} \\ {\text { I. }-\left(4 z^{2}\right)=4\left(-z^{2}\right)}\end{array} $$

Problem 61

Solve each equation for \(x .\) $$ |a x|-b=c $$

Problem 61

Solve each absolute value inequality. \(|2 x+4|-6<0\)

Problem 62

Solve each equation for \(x .\) $$ |c x-d|=a b $$

Problem 62

Solve each absolute value inequality. \(2|x+3| \geq 10\)

Problem 62

Match the property name with the appropriate equation. Opposite of an Opposite $$ \begin{array}{l}{\text { A. } 2(s-t)=2 s-2 t} \\ {\text { B. }-(a-b)=(-1)(a-b)} \\ {\text { C. }(7-y) \div(2 y)=\frac{7-y}{2 y}} \\\ {\text { D. }-[-(x-10)]=x-10} \\ {\text { E. }-(2 t-10)=11-2 t} \\ {\text { F. }-11=2 t+(-11)} \\ {\text { H. }-[3+(-y)]=-3+[-(-y)]} \\ {\text { I. }-\left(4 z^{2}\right)=4\left(-z^{2}\right)}\end{array} $$

Problem 63

Solve each absolute value inequality. \(6|x+9| \leq 36\)

Problem 63

Justifying Steps Name the property used in each step of simplification. $$ \begin{aligned}(3 x+y)+x &=3 x+(y+x) \\ &=3 x+(x+y) \\ &=(3 x+x)+y \\ &=(3 x+1 x)+y \\ &=(3+1) x+y \\ &=4 x+y \end{aligned} $$

Problem 64

Graph each solution. $$ |x| \geq 5 \text { and }|x| \leq 6 $$

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