Chapter 9: Problem 59
Graph each pair of functions on the same screen. Then compare the graphs, listing both similarities and differences in shape, asymptotes, domain, range, and \(y\) -intercepts. $$ y=\left(\frac{1}{4}\right)^{x} \quad y=\left(\frac{1}{4}\right)^{x}-1 $$
Short Answer
Expert verified
The graphs share the same shape but differ by a vertical shift; one is \( y = 0 \) and the other \( y = -1 \).
Step by step solution
01
Understanding the Functions
First, we identify the two functions given in the exercise: 1. The first function is \( y = \left( \frac{1}{4} \right)^{x} \). This is an exponential decay function with base \( \frac{1}{4} \). 2. The second function is \( y = \left( \frac{1}{4} \right)^{x} - 1 \), which is the first function shifted down by 1 unit.
02
Identifying Key Characteristics
For \( y = \left( \frac{1}{4} \right)^{x} \): - **Asymptote:** Horizontal at \( y = 0 \). - **Domain:** All real numbers. - **Range:** \( y > 0 \). - **y-intercept:** \( (0,1) \). For \( y = \left( \frac{1}{4} \right)^{x} - 1 \): - **Asymptote:** Horizontal at \( y = -1 \). - **Domain:** All real numbers. - **Range:** \( y > -1 \). - **y-intercept:** \( (0,0) \).
03
Sketching the Graphs
Plot the two functions on the same graph, noting: 1. Both functions share the same domain and have similar decay towards their respective asymptotes. 2. The graph of \( y = \left( \frac{1}{4} \right)^{x} \) starts at \( (0,1) \) and approaches \( y = 0 \). 3. The graph of \( y = \left( \frac{1}{4} \right)^{x} - 1 \) is the same shape but shifted down by 1 unit, starting at \( (0,0) \) and approaching \( y = -1 \).
04
Comparing the Graphs
**Similarities:** - Both functions are exponential decay functions.- Both have the same base of \( \frac{1}{4} \).- Both extend over all real values of \( x \).**Differences:** - The asymptotes are at different vertical positions (\( y = 0 \) vs. \( y = -1 \)). - The \( y \)-intercepts are different: one at \( (0,1) \) and the other at \( (0,0) \). - The second function is a vertical translation of the first by 1 unit downwards.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Asymptote
In the realm of exponential functions, a key feature to note is the asymptote. An asymptote is a line that a graph approaches but never quite touches. Imagine waving to someone but never reaching them; that's how an asymptote behaves in the graph of a function.
For example, consider the function \( y = \left( \frac{1}{4} \right)^{x} \). This function has a horizontal asymptote at \( y = 0 \). This means as \( x \) moves towards positive or negative infinity, the values of \( y \) get closer and closer to zero but never actually get there. It's like the function is creeping towards a wall it can never reach.
For example, consider the function \( y = \left( \frac{1}{4} \right)^{x} \). This function has a horizontal asymptote at \( y = 0 \). This means as \( x \) moves towards positive or negative infinity, the values of \( y \) get closer and closer to zero but never actually get there. It's like the function is creeping towards a wall it can never reach.
- As \( x \rightarrow -\infty \), \( y \rightarrow 0^+ \).
- As \( x \rightarrow \infty \), \( y \rightarrow 0^+ \), but it never touches \( y = 0 \).
Domain and Range
When graphing exponential functions, it's crucial to determine their domain and range to understand what inputs and outputs are possible. The **domain** of a function refers to all the possible values that \( x \) can take. For the functions we are examining, \( y = \left( \frac{1}{4} \right)^{x} \) and \( y = \left( \frac{1}{4} \right)^{x} - 1 \), both have a domain of **all real numbers**. This means you can plug any value of \( x \) into these functions and obtain a corresponding \( y \) value.
On the other hand, the **range** defines all possible values the function can output or attain. For \( y = \left( \frac{1}{4} \right)^{x} \), the function can output any positive number, but it doesn't reach zero. Thus, the range is \( y > 0 \).
After adjusting to \( y = \left( \frac{1}{4} \right)^{x} - 1 \), the entire function shifts down by 1, affecting its range. Its new range becomes \( y > -1 \), illustrating that while the smallest possible output value approached by the function stays the same distance from zero, every \( y \) value is now shifted by one unit lower.
On the other hand, the **range** defines all possible values the function can output or attain. For \( y = \left( \frac{1}{4} \right)^{x} \), the function can output any positive number, but it doesn't reach zero. Thus, the range is \( y > 0 \).
After adjusting to \( y = \left( \frac{1}{4} \right)^{x} - 1 \), the entire function shifts down by 1, affecting its range. Its new range becomes \( y > -1 \), illustrating that while the smallest possible output value approached by the function stays the same distance from zero, every \( y \) value is now shifted by one unit lower.
Graphing Transformations
Graphing transformations involve shifting, stretching, or compressing a graph of a function. Understanding transformations allows us to predict and sketch how a graph morphs when altered by certain operations.
When we look at the function \( y = \left( \frac{1}{4} \right)^{x} \), it's an exponential decay function that starts at a point on the \( y \)-axis and moves towards the horizontal asymptote as \( x \) increases or decreases. By modifying it to \( y = \left( \frac{1}{4} \right)^{x} - 1 \), we're introducing a **vertical shift**. Each point on the graph of the original function shifts one unit downward.
When we look at the function \( y = \left( \frac{1}{4} \right)^{x} \), it's an exponential decay function that starts at a point on the \( y \)-axis and moves towards the horizontal asymptote as \( x \) increases or decreases. By modifying it to \( y = \left( \frac{1}{4} \right)^{x} - 1 \), we're introducing a **vertical shift**. Each point on the graph of the original function shifts one unit downward.
- The asymptote shifts from \( y = 0 \) to \( y = -1 \).
- The initial starting point (the \( y \)-intercept) moves from \( (0,1) \) to \( (0,0) \).