Chapter 9: Problem 11
Solve each equation. Check your solutions. \(\log _{10} a+\log _{10}(a+21)=2\)
Short Answer
Expert verified
The solution is \( a = 4 \).
Step by step solution
01
Apply the Product Property of Logarithms
We start by using the product property of logarithms, which states that \( \log_b(x) + \log_b(y) = \log_b(xy) \). In our equation, this gives us \( \log_{10}(a(a + 21)) = 2 \).
02
Convert the Logarithmic Equation to an Exponential Equation
Next, we convert the equation from logarithmic form to exponential form. Given \( \log_{10}(b) = c \), this translates to \( b = 10^c \). Applying this to our equation, we get: \( a(a + 21) = 10^2 \), which simplifies to \( a(a + 21) = 100 \).
03
Solve the Quadratic Equation
Expand the left side and rewrite the equation as a standard quadratic equation: \( a^2 + 21a - 100 = 0 \). To solve this, we will use the quadratic formula, \( a = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), with \( a = 1, b = 21, c = -100 \).
04
Calculate the Discriminant
Calculate the discriminant \( b^2 - 4ac \). For our equation, this is \( 21^2 - 4 \times 1 \times (-100) = 441 + 400 = 841 \). Since the discriminant is a perfect square, the roots will be real and rational.
05
Use the Quadratic Formula
Substitute the values into the quadratic formula: \( a = \frac{-21 \pm \sqrt{841}}{2} \). This gives us \( a = \frac{-21 \pm 29}{2} \).
06
Find the Possible Values for a
Calculate the two possible solutions: \( a = \frac{8}{2} = 4 \) and \( a = \frac{-50}{2} = -25 \). However, since \( a \) must be positive (because we are dealing with logarithms), we discard \( a = -25 \). Thus, \( a = 4 \) is the only valid solution.
07
Verify the Solution
We verify the solution by substituting \( a = 4 \) back into the original equation: \( \log_{10}(4) + \log_{10}(25) = \log_{10}(100) = 2 \). The solution satisfies the equation, confirming \( a = 4 \) is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product Property of Logarithms
The product property of logarithms is a powerful tool that makes simplifying some logarithmic expressions much easier. This property states that the logarithm of a product is the sum of the logarithms of its factors. In mathematical terms, for any positive numbers \( x \) and \( y \), and any base \( b \), the property is written as:
After converting and simplifying using this property, we can move on to solve the equation more easily.
- \( \log_b(xy) = \log_b(x) + \log_b(y) \)
- \( \log_{10}(a(a + 21)) = 2 \)
After converting and simplifying using this property, we can move on to solve the equation more easily.
Quadratic Equation
A quadratic equation is a second-order polynomial equation in a single variable \( x \), with the general form:
The quadratic formula ensures that we can find solutions even when factoring is complicated or inefficient.
- \( ax^2 + bx + c = 0 \)
- \( a^2 + 21a - 100 = 0 \)
The quadratic formula ensures that we can find solutions even when factoring is complicated or inefficient.
Discriminant
The discriminant is a vital component of the quadratic formula and helps us understand the nature of the solutions of the quadratic equation. Given a quadratic equation of the form \( ax^2 + bx + c = 0 \), the discriminant \( D \) is calculated as:
- \( D = b^2 - 4ac \)
- \( 21^2 - 4(1)(-100) = 841 \)
- If \( D > 0 \), the equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root (a repeated or double root).
- If \( D < 0 \), the roots are complex (not real).
Logarithmic Form
The logarithmic form of an equation is a way to express exponential relationships. A logarithm answers the question: 'To what power must the base be raised, to produce this number?' For instance, in our equation,
Understanding this form is crucial because it allows us to approach problems needing a conversion between an exponential and a logarithmic perspective. In solving our problem, switching from the logarithmic form to exponential form helps us translate the relationship into a more tractable multiplication problem.
- \( \log_{10}(a^2 + 21a) = 2 \)
Understanding this form is crucial because it allows us to approach problems needing a conversion between an exponential and a logarithmic perspective. In solving our problem, switching from the logarithmic form to exponential form helps us translate the relationship into a more tractable multiplication problem.
Exponential Form
An exponential form is a mathematical expression where numbers are expressed with a base raised to a power. Converting an equation from logarithmic to exponential form involves rewriting it such that the base with its power gives a result. For the given problem's logarithmic equation
- \( \log_{10}(a(a + 21)) = 2 \)
- \( a(a + 21) = 10^2 \)
- \( a(a + 21) = 100 \)