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91Ó°ÊÓ

Graph each rational function. $$ f(x)=\frac{-5}{x+1} $$

Short Answer

Expert verified
The graph has a vertical asymptote at \(x=-1\), a horizontal asymptote at \(y=0\), and passes through the point \((0, -5)\).

Step by step solution

01

Identify the Asymptotes

To identify the vertical asymptote, set the denominator of the rational function equal to zero: \(x+1=0\). Thus, the vertical asymptote is at \(x=-1\). The horizontal asymptote is determined by comparing the degrees of the numerator and the denominator. Since the numerator is a constant \(-5\) and the degree is 0 and the denominator \(x+1\) has degree 1, the horizontal asymptote is \(y=0\).
02

Determine the Intercepts

To find the y-intercept, substitute \(x=0\) into the function: \(f(0) = \frac{-5}{0+1} = -5\). Thus, the y-intercept is \((0, -5)\). There is no x-intercept because the numerator \(-5\) does not equal zero.
03

Plot the Key Features

On the graph, draw the vertical asymptote as a dashed line at \(x=-1\) and the horizontal asymptote as a dashed line at \(y=0\). Plot the y-intercept at \((0, -5)\).
04

Sketch the Graph of the Function

Since \(f(x)=\frac{-5}{x+1}\) is a rational function of the form \(\frac{a}{x+b}\), it will have a hyperbolic shape. As \(x\) approaches \(-1\) from the left, \(f(x)\) tends to \(-\infty\), and as \(x\) approaches \(-1\) from the right, \(f(x)\) tends to \(+\infty\). As \(x\) moves towards \(\infty\) or \(-\infty\), \(f(x)\) approaches the horizontal asymptote, \(y=0\). Use these tendencies to sketch a smooth curve in the first and third quadrants, approaching the asymptotes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Asymptote
A vertical asymptote occurs in a rational function when the denominator equals zero, and the function's value becomes undefined. For the function \( f(x) = \frac{-5}{x+1} \), the vertical asymptote can be found by setting the denominator equal to zero: \( x + 1 = 0 \). Solving this equation gives us \( x = -1 \).
This indicates that as \( x \) approaches \(-1\), the function \( f(x) \) will shoot up to positive infinity or down to negative infinity, implying the function's graph cannot pass this vertical line.
  • Vertical asymptotes divide the graph into distinct sections.
  • Near vertical asymptotes, the function values increase or decrease drastically.
Understanding vertical asymptotes is vital because they show where the function doesn't have a real number value and provide insight into the function's behavior close to those points.
Horizontal Asymptote
Horizontal asymptotes help determine what value a rational function approaches as the input \( x \) becomes very large (positively or negatively). For the function \( f(x) = \frac{-5}{x+1} \), the horizontal asymptote can be determined by looking at the degrees of the numerator and the denominator.
The numerator has a degree of 0, since \(-5\) is a constant. The denominator \( x+1 \) has a degree of 1. Since the degree of the denominator is greater than that of the numerator, the horizontal asymptote is at \( y = 0 \).
This shows that as \( x \) approaches either positive or negative infinity, \( f(x) \) will get closer and closer to 0, but never actually reach it.
  • Horizontal asymptotes describe end behavior of functions.
  • They tell us that the function stabilizes or flattens out as \( x \) goes to infinity.
Recognizing horizontal asymptotes is crucial for predicting the long-term behavior of rational functions.
Intercepts
Intercepts are the points where a function crosses the axes. For the function \( f(x) = \frac{-5}{x+1} \), let's find the intercepts:

**Y-intercept:** This is where the function crosses the y-axis (at \( x = 0 \)). Substituting in gives \( f(0) = \frac{-5}{0+1} = -5 \). So, the y-intercept is \((0, -5)\).
**X-intercept:** This is where the function crosses the x-axis (at \( y = 0 \)). Since the numerator is \(-5\), a non-zero constant, \( f(x) \) does not have an x-intercept in this case.
  • X-intercepts occur when the numerator is zero.
  • Y-intercepts are found by substituting \( x = 0 \) into the function.
  • No x-intercept here means the graph never actually touches the x-axis.
Finding intercepts provides concrete points that help in plotting the graph accurately.
Graph of a Function
Graphing a rational function involves understanding and plotting its asymptotes, intercepts, and its general shape. For \( f(x) = \frac{-5}{x+1} \), follow these steps:
1. Draw the vertical asymptote as a dashed line at \( x=-1 \).
2. Draw the horizontal asymptote as a dashed line at \( y=0 \).
3. Plot the y-intercept at \((0, -5)\).
4. Understand the shape of the graph, which in this case is hyperbolic due to the form \( \frac{a}{x+b} \).
As \( x \) nears \(-1\), approaching from the left, the function heads towards \( -\infty \), while from the right, it goes up towards \( +\infty \). As \( x \) moves towards \( +\infty \) or \( -\infty \), the function approaches \( y=0 \), aligning with the horizontal asymptote.
  • The graph will lie in the first and third quadrants based on this function's behavior.
  • Keep in mind the asymptotic boundaries.
  • Rational functions often have a recognizable shape, such as hyperbolas or curves.
Having a clear graph aids visual understanding and reinforces the importance of analyzing key features.

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