Chapter 6: Problem 67
Determine whether each function has a maximum or a minimum value. Then find the maximum or minimum value of each function. $$ f(x)=-3 x^{2}-18 x+5 $$
Short Answer
Expert verified
The function has a maximum value of -76.
Step by step solution
01
Identify the Quadratic Function
The given function is \( f(x) = -3x^2 - 18x + 5 \), which is a quadratic function of the form \( ax^2 + bx + c \). In this expression, \( a = -3 \), \( b = -18 \), and \( c = 5 \).
02
Determine Concavity
For a quadratic function \( ax^2 + bx + c \), if \( a < 0 \), the parabola opens downwards and the function has a maximum value. Here, since \( a = -3 \), which is less than zero, the parabola opens downwards, implying the function has a maximum value.
03
Find the Vertex
The vertex of a quadratic function \( ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Substitute \( b = -18 \) and \( a = -3 \) into this formula:\[ x = -\frac{-18}{2(-3)} = -\frac{18}{-6} = 3 \]The x-coordinate of the vertex is 3.
04
Calculate the Maximum Value
Substitute \( x = 3 \) back into the function to find the function's maximum value.\[ f(3) = -3(3)^2 - 18(3) + 5 = -3(9) - 54 + 5 = -27 - 54 + 5 = -76 \]Thus, the maximum value of the function is \( -76 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a crucial point that represents the peak or the lowest point of the curve, depending on its direction. In the context of the quadratic function, such as \( f(x) = ax^2 + bx + c \), the vertex provides you with a lot of valuable information about the function. To find the vertex, you can use the formula for the x-coordinate:
- \( x = -\frac{b}{2a} \)
- \( x = -\frac{-18}{2(-3)} = 3 \)
Maximum Value
For any quadratic function, understanding whether it has a maximum or minimum value involves analyzing the coefficient of the \( x^2 \) term. When this coefficient \( a \) is negative, the parabola arches downwards, indicating a maximum value. In the function \( f(x) = -3x^2 - 18x + 5 \), the \( a \) coefficient is \( -3 \), meaning the parabola opens downwards. Consequently, there's a maximum value at the vertex of the parabola. To find the maximum value, substitute the x-coordinate of the vertex back into the function. As illustrated before, if the x-coordinate is \( 3 \), plug \( x = 3 \) into the function:
- \( f(3) = -3(3)^2 - 18(3) + 5 = -76 \)
Concavity of Quadratic Functions
The concavity of a quadratic function helps determine the direction in which its parabola opens. If the function \( f(x) = ax^2 + bx + c \) has a leading coefficient \( a \) that is greater than zero, it opens upwards ('U' shape), indicating a minimum point. Conversely, if \( a \) is less than zero, the parabola opens downwards, indicating a maximum point.In the given quadratic function \( f(x) = -3x^2 - 18x + 5 \), the \( a \) coefficient equals \(-3\). This negative value tells us:
- The parabola opens downwards.
- There exists a maximum value.