Chapter 6: Problem 48
Given a function and one of its zeros, find all of the zeros of the function. \(f(x)=x^{3}+5 x^{2}+9 x+45 ;-5\)
Short Answer
Expert verified
The zeros are \(-5\), \(3i\), and \(-3i\).
Step by step solution
01
Understanding the Problem
We are given the function \(f(x) = x^3 + 5x^2 + 9x + 45\) and one of its zeros, \(-5\). This means that \(f(-5) = 0\). Our goal is to find all the zeros of the function.
02
Synthetic Division
To find other zeros, perform synthetic division using \(-5\) as the divisor. Arrange the coefficients of \(f(x)\) which are \(1, 5, 9, 45\). Start with the leading coefficient (1), multiply \(-5\) to it, add to the next coefficient, and repeat.
03
Carry Out Synthetic Division
1. Bring down the 1. 2. Multiply \(1\) by \(-5\) to get \(-5\). Add to 5 to get 0. 3. Multiply 0 by \(-5\) to get 0. Add to 9 to get 9. 4. Multiply 9 by \(-5\) to get \(-45\). Add to 45 to get 0.The quotient polynomial is \(x^2 + 9\) and remainder is 0, confirming \(-5\) is indeed a zero.
04
Finding Zeros of the Quotient Polynomial
Now evaluate \(x^2 + 9 = 0\). Solve for \(x\) by subtracting 9 from both sides and taking the square root:\[x^2 = -9\]\[x = \pm\sqrt{-9}\]This results in the complex zeros \(x = \pm 3i\).
05
Conclusion of Zeros
Thus, the function \(f(x)\) has the zeros \(-5\), \(3i\), and \(-3i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Synthetic Division
Synthetic division is a streamlined method for dividing a polynomial by a binomial of the form \(x - c\). It simplifies the division process and helps to find zeroes quickly.
Instead of writing the whole polynomial, you use only the coefficients:
This process reduces the polynomial's degree by one, helping to further factor and find other zeros.
Instead of writing the whole polynomial, you use only the coefficients:
- Write the coefficients of the polynomial in a row.
- Write the zero, or root, you know outside the bracket.
- Bring down the first coefficient.
- Multiply this coefficient by the root and add the result to the next coefficient.
- Repeat this process for all coefficients.
This process reduces the polynomial's degree by one, helping to further factor and find other zeros.
Complex Zeros
When finding zeros of a polynomial, you may encounter complex numbers. These zeros occur when taking square roots of negative numbers. Recall that the imaginary unit \(i\) is defined by \(i^2 = -1\).
For example, if you have an expression like \(x^2 + 9 = 0\), solving gives \(x = \pm\sqrt{-9}\), which results in \(x = \pm 3i\).
Complex zeros often come in conjugate pairs. This means if \(3i\) is a zero, then \(-3i\) is also a zero.
For example, if you have an expression like \(x^2 + 9 = 0\), solving gives \(x = \pm\sqrt{-9}\), which results in \(x = \pm 3i\).
Complex zeros often come in conjugate pairs. This means if \(3i\) is a zero, then \(-3i\) is also a zero.
- They provide valuable insight into the polynomial's symmetry.
- Even if the polynomial's degree is odd, complex numbers could be part of its zeros.
Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients.
They follow the format \(f(x) = a_nx^n + a_{n-1}x^{n-1} + \, ... \, + a_1x + a_0\), where \(a_n\) are the coefficients and \(x\) is the variable.
These zeros are significant in determining the function's graph behavior and intersections with the x-axis.
Learning to find and interpret these zeros helps in understanding the broader concepts of calculus and algebra.
They follow the format \(f(x) = a_nx^n + a_{n-1}x^{n-1} + \, ... \, + a_1x + a_0\), where \(a_n\) are the coefficients and \(x\) is the variable.
- Higher degree polynomials have more complex structures and potentially more zeros.
- A polynomial of degree \(n\) can have up to \(n\) zeros, which might be real or complex.
These zeros are significant in determining the function's graph behavior and intersections with the x-axis.
Learning to find and interpret these zeros helps in understanding the broader concepts of calculus and algebra.