/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Write each expression in quadrat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write each expression in quadratic form, if possible. $$ 6 x^{\frac{2}{5}}-4 x^{\frac{1}{5}}-16 $$

Short Answer

Expert verified
The expression is quadratic in terms of \(u\), where \(u = x^{\frac{1}{5}}\).

Step by step solution

01

Identify substitution variable

Notice that the terms in the expression have powers of \(x\) that are fractional. Here, the smallest power is \(\frac{1}{5}\). We will use a substitution where \(u = x^{\frac{1}{5}}\). This simplifies the fractional powers.
02

Rewrite the expression in terms of the substitution variable

Replacing \(x^{\frac{1}{5}}\) with \(u\), the expression becomes: \[6 (x^{\frac{1}{5}})^2 - 4 x^{\frac{1}{5}} - 16\]This simplifies to:\[6u^2 - 4u - 16\]
03

Confirm quadratic form

Now, verify that the rewritten expression, \(6u^2 - 4u - 16\), is indeed in quadratic form, \(au^2 + bu + c\), with \(a = 6\), \(b = -4\), and \(c = -16\). This confirms it's a quadratic expression in terms of \(u\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Form
When we talk about quadratic form, we're dealing with a polynomial expression specifically of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( x \) is the variable. In simple terms, it's a math expression that includes a squared term, a linear term, and a constant.
Quadratic equations are a type of polynomial that describe a parabola when plotted on a graph. These equations can model a wide range of real-world situations, like projectiles in motion or areas of certain shapes. Recognizing when an expression can be rearranged into this form is crucial, especially for solving complex problems.
To rewrite an expression in quadratic form, it's important to identify if it matches or can be transformed into this structure. In our example, we're transforming an expression with fractional exponents to fit this recognizable pattern. We're using substitution to help make it easier to recognize and handle.
Substitution Method
The substitution method is an ingenious way to simplify complex mathematical expressions by replacing variables with other terms, making them easier to work with. It's particularly useful for expressions involving fractional exponents.
In our example, we required simplifying \( 6x^{\frac{2}{5}} - 4x^{\frac{1}{5}} - 16 \). We noticed a common smaller exponent, \( x^{\frac{1}{5}} \), which we replaced with the variable \( u \). This lets us transform the original equation into something more manageable: \( 6u^2 - 4u - 16 \).
By doing this substitution:
  • The power \( x^{\frac{2}{5}} \) becomes \( u^2 \), since \( u = x^{\frac{1}{5}} \).
  • It creates a clearer quadratic expression, easier to interpret and solve like any other quadratic equation.
This method helps reduce clutter, making it possible to verify and solve by focusing only on terms in a straightforward quadratic structure.
Fractional Exponents
Fractional exponents might look a bit intimidating at first, but they're fundamentally about relating roots and powers. A fractional exponent like \( x^{\frac{1}{5}} \) signifies the fifth root of \( x \), while \( x^{\frac{2}{5}} \) means \( (x^{\frac{1}{5}})^2 \).
Handling expressions with them requires understanding that:
  • The numerator of the fraction indicates the power. Here, \( x^{2} = (x^{\frac{1}{5}})^2 \).
  • The denominator represents the root, like \( x^{\frac{1}{5}} \) is the fifth root of \( x \).
Understanding and manipulating fractional exponents is crucial for simplifying expressions, especially when they're part of more complex equations. In this exercise, recognizing the common fractional exponent enabled the substitution method, simplifying the transition to a quadratic form.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For Exerises \(26-31\) , complete each of the following. a. Graph each funnction by making a table of values. b. Determine the consecutive integer values of \(x\) between which each real zero is located. C. Estimate the \(x\) -coordinates at which the relative maxima and relative minima occur. $$ f(x)=2 x^{4}-4 x^{3}-2 x^{2}+3 x-5 $$

Use a graphing calculator to estimate the \(x\) -coordinates at which the maxima and minima of each function occur. Round to the nearest hundredth. $$ f(x)=x^{3}+x^{2}-7 x-3 $$

For Exercises 32 and \(33,\) use the following information. The average height (in inches) for boys ages 1 to 20 can be modeled by the equation \(B(x)=-0.001 x^{4}+0.04 x^{3}-0.56 x^{2}+5.5 x+25\) , where \(x\) is the age (in years). The average height for girls ages 1 to 20 is modeled by the equation \(G(x)=-0.0002 x^{4}+0.006 x^{3}-0.14 x^{2}+3.7 x+26\) . Graph both equations by making a table of values. Use \(x=\\{0,2,4,6,8,10,\) \(12,14,16,18,20 \\}\) as the domain. Round values to the nearest inch.

Use synthetic substitution to find \(g(3)\) and \(g(-4)\) for each function. $$ g(x)=x^{6}-4 x^{4}+3 x^{2}-10 $$

BOATING. For Exercises 30 and \(31,\) use the following information. A motor boat traveling against waves accelerates from a resting position. Suppose the speed of the boat in feet per second is given by the function \(f(t)=-0.04 t^{4}+0.8 t^{3}+0.5 t^{2}-t,\) where \(t\) is the time in seconds. It takes 6 seconds for the boat to travel between two buoys while it is accelerating. Use synthetic substitution to find \(f(6)\) and explain what this means.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.