/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Simplify. $$ \frac{9 a^{3} b... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify. $$ \frac{9 a^{3} b^{2}-18 a^{2} b^{3}}{3 a^{2} b} $$

Short Answer

Expert verified
The simplified expression is \( 3ab - 6b^2 \).

Step by step solution

01

Factor the Numerator

The numerator is given by \( 9a^3b^2 - 18a^2b^3 \). Start by factoring out the greatest common factor (GCF) from the terms in the numerator. The GCF of these terms is \( 9a^2b^2 \). Factoring this out, we get: \[ 9a^2b^2(a - 2b). \]
02

Simplify the Fraction

Now substitute the factored form of the numerator back into the expression, resulting in \( \frac{9a^2b^2(a - 2b)}{3a^2b} \). Begin simplifying by canceling common terms between the numerator and the denominator. \[ \frac{9a^2b^2(a - 2b)}{3a^2b} = \frac{9}{3} \cdot \frac{a^2}{a^2} \cdot \frac{b^2}{b} \cdot (a - 2b). \]
03

Perform the Cancellation

Continue simplifying. First, \( \frac{9}{3} = 3 \). Also, the \( a^2 \) terms cancel each other out and \( \frac{b^2}{b} = b \). Now the expression simplifies to \[ 3b(a - 2b). \]
04

Final Expression

Multiply the remaining terms to express the simplified result: \( 3b(a - 2b) = 3ab - 6b^2 \). Hence, the simplified form is \( 3ab - 6b^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Greatest Common Factor
When working with polynomials, finding the Greatest Common Factor (GCF) is the first step in simplification. The GCF is the highest number or greatest polynomial term that divides into each term of the given expression without leaving a remainder. In the exercise you provided, the terms in the numerator are \(9a^3b^2\) and \(-18a^2b^3\). To find their GCF, first look at the coefficients 9 and 18. The greatest common factor of these numbers is 9. Then, examine the variables:- For \(a^3\) and \(a^2\), the GCF is \(a^2\) because it is the smallest power of \(a\) appearing as a factor in both terms.- For \(b^2\) and \(b^3\), the GCF is \(b^2\) because it is the smallest power of \(b\) that divides both terms.Thus, the GCF for the entire expression is \(9a^2b^2\). By factoring this out, you create a simpler expression that is easier to work with.
Factoring Polynomials
Factoring polynomials involves expressing a polynomial as a product of its factors. It simplifies the polynomial and makes it easier to manipulate or simplify further, as in the case of our given exercise.Once the GCF \(9a^2b^2\) was factored out from the numerator \(9a^3b^2 - 18a^2b^3\), it allowed us to rewrite the expression in a simplified form: \[9a^2b^2(a - 2b)\] This factored expression reveals any potential for simplification in subsequent operations involving algebraic expressions.- The term \(a - 2b\) is known as the factored form of the polynomial \(a^3b^2 - 2a^2b^3\) since it simplifies the original polynomial and often helps in cancelling terms elsewhere, as we see in rational expressions.
Rational Expressions
Rational expressions are fractions where the numerator and the denominator are polynomials. Simplifying these expressions can often appear complex, but understanding the basics of factoring and finding common factors can significantly ease the process.In the exercise given, the rational expression is:\[ \frac{9a^3b^2 - 18a^2b^3}{3a^2b} \]By factoring the numerator, we simplify it into a form \(9a^2b^2(a - 2b)\). This allows for cancellation of matching terms in the numerator and denominator. Specifically, the \(a^2\) and \(b\) from the denominator cancel with parts of \(9a^2b^2\) in the numerator. This reduction simplifies the fraction to a simpler expression:\[ 3b(a - 2b) \] Ultimately, simplifying rational expressions involves:
  • Factoring the numerator and the denominator to their simplest forms.
  • Canceling any common factors present in both the numerator and the denominator.
This reduces the complexity of the expression and results in a cleaner, more manageable form.

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Most popular questions from this chapter

For Exercises \(11-18,\) complete each of the following. a. Graph each function by making a table of values. b. Determine the consecutive integer values of \(x\) between which each real zero is located. C. Estimate the \(x\) -coordinates at which the relative maxima and relative minima occur. $$ f(x)=x^{3}-3 x^{2}+2 $$

PERSONAL FINANCE For Exercises \(38-41,\) use the following information. Zach has purchased some home theater equipment for \(\$ 2000,\) which he is financing through the store. He plans to pay \(\$ 340\) per month and wants to have the balance paid off after six months. The formula \(B(x)=2000 x^{6}-\) 340\(\left(x^{5}+x^{4}+x^{3}+x^{2}+x+1\right)\) represents his balance after six months if \(x\) represents 1 plus the monthly interest rate (expressed as a decimal). Find his balance after 6 months if the annual interest rate is 12\(\% .\) (Hint: The monthly interest rate is the annual rate divided by \(12,\) so \(x=1.01 . )\)

For Exercises \(11-18,\) complete each of the following. a. Graph each function by making a table of values. b. Determine the consecutive integer values of \(x\) between which each real zero is located. C. Estimate the \(x\) -coordinates at which the relative maxima and relative minima occur. $$ f(x)=x^{3}-2 x^{2}+6 $$

For Exercises \(39-41,\) sketch a graph of each polynomial. odd-degree polynomial function with one relative maximum and one relative minimum; the leading coefficient is negative

Solve each matrix equation or system of equations by using inverse matrices. $$ \left[\begin{array}{rr}{5} & {-7} \\ {-3} & {4}\end{array}\right] \cdot\left[\begin{array}{c}{m} \\\ {n}\end{array}\right]=\left[\begin{array}{r}{-1} \\ {1}\end{array}\right] $$

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