Chapter 3: Problem 11
Solve each system of equations. \(5 x+2 y=4\) \(3 x+4 y+2 z=6\) \(7 x+3 y+4 z=29\)
Short Answer
Expert verified
x = 2, y = -3, z = 6
Step by step solution
01
Identify the system of equations
The given system of equations is:1. \(5x + 2y = 4\)2. \(3x + 4y + 2z = 6\)3. \(7x + 3y + 4z = 29\)We need to find the values of \(x\), \(y\), and \(z\) that satisfy all three equations simultaneously.
02
Express one variable in terms of others
From the first equation \(5x + 2y = 4\), solve for \(x\) in terms of \(y\):\[x = \frac{4 - 2y}{5}\]
03
Substitute expression into other equations
Substitute \(x = \frac{4 - 2y}{5}\) into the second and third equations:For the second equation:\[3\left(\frac{4 - 2y}{5}\right) + 4y + 2z = 6\]Rewrite it:\[\frac{12 - 6y}{5} + 4y + 2z = 6\]Multiply everything by 5 to eliminate fractions:\[12 - 6y + 20y + 10z = 30\]Simplify it:\[14y + 10z = 18\]\For the third equation:\[7\left(\frac{4 - 2y}{5}\right) + 3y + 4z = 29\]Rewrite it:\[\frac{28 - 14y}{5} + 3y + 4z = 29\]Multiply everything by 5:\[28 - 14y + 15y + 20z = 145\]Simplify it:\[y + 20z = 117\]
04
Solve the new system of equations
Now, solve the new system of two equations:1. \(14y + 10z = 18\)2. \(y + 20z = 117\)From the second equation, solve for \(y\):\[y = 117 - 20z\]Substitute back into the first equation:\[14(117 - 20z) + 10z = 18\]Calculate:\[1638 - 280z + 10z = 18\]Simplify:\[-270z = -1620\]Divide by -270:\[z = 6\]
05
Find the value of y
Substitute \(z = 6\) back into \(y = 117 - 20z\):\[y = 117 - 20(6)\]Calculate:\[y = 117 - 120\]\[y = -3\]
06
Find the value of x
Substitute \(y = -3\) back into \(x = \frac{4 - 2y}{5}\):\[x = \frac{4 - 2(-3)}{5}\]Calculate:\[x = \frac{4 + 6}{5}\]\[x = \frac{10}{5}\]\[x = 2\]
07
Verify the solution
Verify that \(x = 2\), \(y = -3\), \(z = 6\) satisfy all original equations:- For the first equation: \(5(2) + 2(-3) = 10 - 6 = 4\) (True)- For the second equation: \(3(2) + 4(-3) + 2(6) = 6 - 12 + 12 = 6\) (True)- For the third equation: \(7(2) + 3(-3) + 4(6) = 14 - 9 + 24 = 29\) (True)
08
Conclusion
The values \(x = 2\), \(y = -3\), \(z = 6\) solve the system of equations and satisfy all of the original equations.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Equations
Linear equations are mathematical expressions that represent lines when graphed on a coordinate plane. They consist of variables multiplied by constants and added together. In this context, we have a set of linear equations in three variables: \(x\), \(y\), and \(z\). Each equation has variables with different coefficients:
- \(5x + 2y = 4\)
- \(3x + 4y + 2z = 6\)
- \(7x + 3y + 4z = 29\)
Substitution Method
The substitution method is a technique for solving a system of equations where you solve one equation for one variable and then substitute that expression into the other equation(s). In our exercise, we started with the first equation \(5x + 2y = 4\) and solved for \(x\) in terms of \(y\):
- \(x = \frac{4 - 2y}{5}\)
Solution Verification
After calculating potential solutions, it is crucial to verify them by substituting back into the original set of equations. In our exercise, the values found were \(x = 2\), \(y = -3\), and \(z = 6\). Verification involves checking:
- First equation: \(5(2) + 2(-3) = 10 - 6 = 4\), which is true.
- Second equation: \(3(2) + 4(-3) + 2(6) = 6 - 12 + 12 = 6\), also true.
- Third equation: \(7(2) + 3(-3) + 4(6) = 14 - 9 + 24 = 29\), again true.
Algebraic Manipulation
Algebraic manipulation is a fundamental skill used to rearrange equations and expressions, making them simpler to evaluate. In this exercise, we employed several algebraic techniques:
- Solving for one variable in terms of others in a single equation, such as obtaining \(x = \frac{4 - 2y}{5}\) from \(5x + 2y = 4\).
- Substituting expressions from one equation into others to eliminate variables, reducing the complexity of the system.
- Ensuring balance by performing the same operations on both sides of the equation, evidenced by multiplying entire equations to clear denominators.
- Simplifying resulting equations to make them more straightforward to solve, such as turning \(14y + 10z = 18\) into a form that is easier to analyze.