Chapter 14: Problem 55
PREREQUISITE SKILL Graph each pair of functions on the same set of axes. $$ y=3 x^{2}, y=3 x^{2}-4 $$
Short Answer
Expert verified
Plot the parabolas of \( y = 3x^2 \) and \( y = 3x^2 - 4 \) on the same graph, showing the downward shift of the second graph by 4 units.
Step by step solution
01
Understand the Functions
We have two functions: \( y = 3x^2 \) and \( y = 3x^2 - 4 \). The first is a standard quadratic function, while the second is the same quadratic function shifted downward by 4 units.
02
Identify the Shape of the Graphs
Both functions are parabolas that open upwards. The first function \( y = 3x^2 \) has its vertex at the origin (0,0). The second function \( y = 3x^2 - 4 \) also forms a parabola but has its vertex shifted downward.
03
Find the Vertex of Each Parabola
For \( y = 3x^2 \), since it's in the form \( y = ax^2 \), the vertex is at (0,0). For \( y = 3x^2 - 4 \), the vertex is at (0,-4) because the entire graph of \( y = 3x^2 \) has been translated 4 units downward.
04
Plot Key Points for y = 3x^2
Choose a few x-values to plot for the first parabola. For example, if \( x = 0 \), \( y = 0 \); if \( x = 1 \), \( y = 3 \); and if \( x = -1 \), \( y = 3 \). This helps in sketching the parabola.
05
Plot Key Points for y = 3x^2 - 4
For the second function, add the downward shift in values. If \( x = 0 \), then \( y = -4 \); if \( x = 1 \), then \( y = -1 \); if \( x = -1 \), \( y = -1 \). Plot these points to sketch the parabola.
06
Draw the Graphs
On the same set of axes, sketch the parabola \( y = 3x^2 \) by plotting its points and drawing a smooth curve through them. Then sketch the parabola \( y = 3x^2 - 4 \) and plot its points, showing it shifted 4 units downward. Make sure the vertex shift is clearly visible.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabolas
Parabolas are U-shaped curves that you often see when graphing quadratic functions. These come from equations such as \( y = ax^2 + bx + c \). In our exercise, the given functions are simpler forms of quadratic equations, specifically \( y = 3x^2 \) and \( y = 3x^2 - 4 \). Both are examples of parabolas, distinguished by their references to a principal point called the vertex.
Both functions provided in the exercise have their parabolas opening upwards because the coefficient of \( x^2 \), called \( a \), is positive (in this case, \( a = 3 \)).
Both functions provided in the exercise have their parabolas opening upwards because the coefficient of \( x^2 \), called \( a \), is positive (in this case, \( a = 3 \)).
- For \( y = 3x^2 \), the vertex, or the lowest point of the parabola, is at the origin, which is point (0,0).
- For \( y = 3x^2 - 4 \), the vertex is found directly below the origin at (0,-4).
Vertex Form
The vertex form of a quadratic function is another useful way to write quadratic equations, particularly when you need to quickly find the vertex of a parabola. Its general structure is \( y = a(x-h)^2 + k \), where the vertex of the parabola is at \((h, k)\). Though the exercise used standard form, understanding vertex form is still valuable.
For instance:
For instance:
- Consider \( y = a(x-0)^2 + 0 \), which is essentially \( y = ax^2 \). Here, the vertex is at (0,0), matching the vertex for \( y = 3x^2 \).
- Similarly, \( y = a(x-0)^2 -4 \) implies a vertex of (0,-4), explaining \( y = 3x^2 - 4 \).
Graph Transformations
Graph transformations involve changes to the position, size, or orientation of a graph. In the case of the functions \( y = 3x^2 \) and \( y = 3x^2 - 4 \), the primary transformation is a vertical shift. Understanding these shifts allows you to graph functions more effectively.
The transformation illustrated in this exercise is a downward shift:
The transformation illustrated in this exercise is a downward shift:
- \( y = 3x^2 \) remains at its original position with the vertex at (0,0).
- \( y = 3x^2 - 4 \) represents a graph that has been shifted 4 units downward. This results in the vertex moving to (0, -4).