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Find the exact value of each function. \(\sin 690^{\circ}\)

Short Answer

Expert verified
The exact value of \(\sin 690^{\circ}\) is \(-\frac{1}{2}\).

Step by step solution

01

Understanding the Angle

The angle given is \[ 690^{\circ} \].This angle is greater than \(360^{\circ}\), so it makes sense to find an equivalent angle within the first cycle of the unit circle, \([0^{\circ}, 360^{\circ})\). This can be done by subtracting multiples of \(360^{\circ}\).
02

Reduce the Angle

Determine how many full rotations of \(360^{\circ}\) can be subtracted from \[ 690^{\circ} \].Since \[ 690^{\circ} - 360^{\circ} = 330^{\circ}, \]an equivalent angle is \[ 330^{\circ} \].It indicates that\( \sin 690^{\circ} = \sin 330^{\circ} \).
03

Evaluate the Sine Function at 330°

Now, look for the sine of \( 330^{\circ} \).Since \( 330^{\circ} \) is in the fourth quadrant, where the sine is negative and considering the reference angle \( 360^{\circ} - 330^{\circ} = 30^{\circ}, \)the value is \( -\frac{1}{2}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Circle
The unit circle is a fundamental concept in trigonometry. It is a circle with a radius of 1 centered at the origin of a coordinate system. The unit circle allows us to easily evaluate trigonometric functions like sine, cosine, and tangent for any angle.

All angles on the unit circle are measured from the positive x-axis, moving counter-clockwise. This makes understanding and identifying angle positions straightforward. Each point on the unit circle corresponds to
  • an angle measured in degrees or radians,
  • a coordinate pair consisting of \(x\) and \(y\) values,
  • these coordinates directly relate to the cosine and sine of the angle.
For example, an angle \( \theta\) on the unit circle will have coordinates \((\cos \theta, \sin \theta)\).

By knowing these coordinates, you can easily determine the value of trigonometric functions and understand the symmetry and periodicity inherent in trigonometry.
Reference Angles
Reference angles are key to simplifying the computation of trigonometric functions. A reference angle is the smallest acute angle a given angle makes with the x-axis. Understanding reference angles can help you find the values of trigonometric functions for non-standard angles.

To find the reference angle:
  • For angles in the first quadrant, the reference angle is the angle itself.
  • In the second quadrant, it's \(180^\circ - \theta\).
  • For the third quadrant, you calculate \((\theta - 180^\circ)\).
  • In the fourth quadrant, it's \(360^\circ - \theta\).
In the case of finding \(\sin 690^\circ\), the angle is equivalent to \(330^\circ\) when reduced, and \(330^\circ\) has a reference angle of \(30^\circ\).

Reference angles allow the determination of trigonometric function values based on simpler, commonly memorized angles like \(0^\circ, 30^\circ, 45^\circ, 60^\circ, \) and \(90^\circ\).
Quadrants
The coordinate system is divided into four quadrants, each one formed by the intersection of the x-axis and y-axis. Understanding which quadrant an angle falls into helps determine the sign of its trigonometric functions.

The quadrants are labeled as follows:
  • Quadrant I: All trigonometric functions are positive.
  • Quadrant II: Sine is positive, while cosine and tangent are negative.
  • Quadrant III: Tangent is positive, while sine and cosine are negative.
  • Quadrant IV: Cosine is positive, but sine and tangent are negative.
In our example of \(\sin 690^\circ\), we reduced this angle to \(330^\circ\) which is in the fourth quadrant. Here, sine values are negative because only cosine remains positive.

This quadrant understanding is crucial when determining the exact value of trigonometric functions for any angle, helping predict whether those values will be positive or negative once calculated.

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Most popular questions from this chapter

Fountains Architects who design fountains know that both the height and distance that a water jet will project is dependent on the angle \(\theta\) at which the water is aimed. For a given angle \(\theta\) , the ratio of the maximum height \(H\) of the parabolic arc to the horizontal distance \(D\) it travels is given by \(\frac{H}{D}=\frac{1}{4} \tan \theta .\) Find the value of \(\theta,\) to the nearest degree, that will cause the arc to go twice as high as it travels horizontally.

Find each value. Write angle measures in radians. Round to the nearest hundredth. $$ \cot \left(\sin ^{-1} \frac{5}{6}\right) $$

Determine whether each triangle has no solution, one solution, or two solutions. Then solve each triangle. Round measures of sides to the nearest tenth and measures of angles to the nearest degree. $$ A=68^{\circ}, a=3, b=5 $$

RADIO A radio station providing local tourist information has transmitter on Beacon Road, 8 miles from where it intersects with the interstate highway. If the radio station has a range of 5 miles, between what two distances from the intersection can cars on the interstate tune in to hear this information?

OPTICS You may have polarized sunglasses that eliminate glare by polarizing the light. When light is polarized, all of the wayes are traveling in parallel planes. Suppose horizontally-polarized light with intensity \(I_{0}\) strikes a polarizing filter with its axis at an angle of \(\theta\) with the horizontal. The intensity of the transmitted light \(I_{l}\) and \(\theta\) are related by the equation \(\cos \theta=\sqrt{\frac{1}{I_{0}}} \cdot\) If one fourth of the polarized light is transmitted through the lens, what angle does the transmission axis of the filter make with the horizontal?

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