Chapter 11: Problem 38
Find \(S_{n}\) for each geometric series described. $$ a_{1}=162, r=\frac{1}{3}, n=6 $$
Short Answer
Expert verified
The sum of the first 6 terms, \( S_6 \), is approximately 243.52.
Step by step solution
01
Understand the Formula for Sum of a Geometric Series
The sum of the first \( n \) terms of a geometric series is given by the formula: \[ S_n = a_1 \frac{1-r^n}{1-r} \] where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms.
02
Substitute the Values into the Formula
Substitute the given values into the formula: \( a_1 = 162 \), \( r = \frac{1}{3} \), and \( n = 6 \). This gives:\[ S_6 = 162 \frac{1-(\frac{1}{3})^6}{1-\frac{1}{3}} \]
03
Calculate \( r^n \)
Calculate the value of \( (\frac{1}{3})^6 \):\[ (\frac{1}{3})^6 = \frac{1}{729} \]
04
Calculate the Numerator
Substitute \( (\frac{1}{3})^6 = \frac{1}{729} \) into the numerator:\[ 1 - (\frac{1}{3})^6 = 1 - \frac{1}{729} = \frac{728}{729} \]
05
Calculate the Denominator
Calculate the denominator:\[ 1 - \frac{1}{3} = \frac{2}{3} \]
06
Find \( S_n \) by Substituting Back
Now substitute the values back into the formula for \( S_6 \):\[ S_6 = 162 \cdot \frac{ \frac{728}{729} }{ \frac{2}{3} } \]
07
Simplify the Expression
Simplify the expression:\[ S_6 = 162 \cdot \frac{728}{729} \cdot \frac{3}{2} \]Calculate:\[ S_6 = 162 \cdot \frac{728}{729} \cdot 1.5 = 162 \cdot \frac{364}{243} \]
08
Perform the Final Calculation
Calculate \( S_6 = 162 \cdot \frac{364}{243} \):\[ S_6 = 162 \cdot 1.498 = 242.52 \] Thus, \( S_6 = 243.52 \) (rounded to two decimal places).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of a Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. The sum of the first \( n \) terms of this sequence is what we call the sum of a geometric series. To find this sum, we use the formula: \\[ S_n = a_1 \frac{1-r^n}{1-r} \] \where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms. \
The formula derives from the fact that each term in a geometric series builds upon the previous one based on a consistent pattern defined by the common ratio. \
The formula derives from the fact that each term in a geometric series builds upon the previous one based on a consistent pattern defined by the common ratio. \
- The numerator \( 1 - r^n \) acts to subtract a small fraction of the total given the decreasing nature of a convergent geometric series when \(|r| < 1\).
- The denominator \( 1 - r \) essentially reverses the multiplication by \( r \), thus cumulatively summarizing the series when repeated with each term.
Common Ratio
The common ratio in a geometric series is the factor by which we multiply each term to get the next term in the sequence. It is usually represented by the letter \( r \). In our given exercise, the common ratio is \( \frac{1}{3} \). \
Understanding the common ratio is crucial because:
Understanding the common ratio is crucial because:
- The value of \( r \) determines the nature of the series—if the terms will grow larger, shrink, or remain constant.
- A common ratio greater than 1 tends to make the series grow exponentially.
- A common ratio between 0 and 1 will typically cause the terms to decrease towards zero, making it a convergent series.
- If the common ratio is negative, the terms will alternate in sign.
Number of Terms
The number of terms, postulated with the symbol \( n \), denotes how many elements of the series are included when computing the sum. In our example exercise, \( n = 6 \), indicating that the first six terms of the series should be considered. The total \( n \) affects the extent and accuracy of the geometric series' sum, as it directly influences the formula \( S_n = a_1 \frac{1-r^n}{1-r} \). \
More terms equate to a more precise approximation of the series' behavior, especially in finite series. \
More terms equate to a more precise approximation of the series' behavior, especially in finite series. \
- For a given \( n \), if the common ratio \( r \) is a fraction, an increased \( n \) will make \( r^n \) very small, leading the series sum to stabilize or converge.
- In contrast, if \( r \) is greater than 1, the series sum can grow very large with a bigger \( n \).
- For finite sequences, the number of terms provides an endpoint, ultimately giving a practical boundary to an otherwise infinite mathematical model.