Chapter 11: Problem 2
Expand each power. $$ (t+2)^{6} $$
Short Answer
Expert verified
The expanded expression is \(t^6 + 12t^5 + 60t^4 + 160t^3 + 240t^2 + 192t + 64\).
Step by step solution
01
Understand the Binomial Theorem
The expression \((t+2)^6\) can be expanded using the Binomial Theorem, which states that \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). Identify \(a = t\) and \(b = 2\), and \(n = 6\).
02
Calculate the Binomial Coefficients
For the expansion, calculate the coefficients \(\binom{6}{k}\) for \(k = 0\) to \(6\). These coefficients are 1, 6, 15, 20, 15, 6, and 1.
03
Apply the Binomial Theorem
Using the coefficients calculated, the expanded form is:\[ \sum_{k=0}^{6} \binom{6}{k} t^{6-k} 2^k = \binom{6}{0} t^6 (2^0) + \binom{6}{1} t^5 (2^1) + \ldots + \binom{6}{6} t^0 (2^6) \].
04
Write Each Term
Substitute into the expansion:- \(\binom{6}{0} t^6 (2^0) = 1 \cdot t^6\)- \(\binom{6}{1} t^5 (2^1) = 6 \cdot t^5 \cdot 2\)- \(\binom{6}{2} t^4 (2^2) = 15 \cdot t^4 \cdot 4\)- \(\binom{6}{3} t^3 (2^3) = 20 \cdot t^3 \cdot 8\)- \(\binom{6}{4} t^2 (2^4) = 15 \cdot t^2 \cdot 16\)- \(\binom{6}{5} t^1 (2^5) = 6 \cdot t \cdot 32\)- \(\binom{6}{6} t^0 (2^6) = 1 \cdot 64\).
05
Simplify Each Term
Simplify each of the terms calculated in the previous step:- \(t^6\)- \(12t^5\)- \(60t^4\)- \(160t^3\)- \(240t^2\)- \(192t\)- \(64\).
06
Combine All Terms
Write the final expanded form by combining all the terms:\(t^6 + 12t^5 + 60t^4 + 160t^3 + 240t^2 + 192t + 64\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficient
The binomial coefficient is a fundamental component of the Binomial Theorem. It is denoted as \(\binom{n}{k}\), read as "n choose k," and represents the number of ways to select \(k\) elements from a set of \(n\) elements, without considering the order. In the expansion of \((t+2)^6\), these coefficients are crucial to determining each term's multiplicative factor.
To calculate a binomial coefficient, use the formula:
To calculate a binomial coefficient, use the formula:
- \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\)
- \(\binom{6}{0} = 1\)
- \(\binom{6}{1} = 6\)
- \(\binom{6}{2} = 15\)
- \(\binom{6}{3} = 20\)
- \(\binom{6}{4} = 15\)
- \(\binom{6}{5} = 6\)
- \(\binom{6}{6} = 1\)
Polynomial Expansion
Polynomial expansion refers to expressing a power of a binomial, such as \((t+2)^6\), as a sum of terms. Each term is a product of a binomial coefficient, a power of \(t\), and a power of the constant term, which in this case is 2. The Binomial Theorem provides a systematic approach to achieving this expansion.
Using the theorem:
Applying these rules to \((t+2)^6\):
Using the theorem:
- Expand \((a+b)^n\) using the sum \(\sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).
Applying these rules to \((t+2)^6\):
- The first term is \(\binom{6}{0} t^6 \times 2^0 = t^6\).
- Continue this for each following \(k\) until \(6\).
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and mathematical operations. In this context, the binomial expression \((t+2)^6\) is simply a specific type of algebraic expression that involves raising a binomial to a power.
Understanding how to manipulate algebraic expressions using rules like the Binomial Theorem is important because:
Working with algebraic expressions emphasizes translating between different forms – from a simple binomial to an expanded polynomial. This skill is particularly useful in higher mathematics, logical reasoning, and problem-solving in real-world applications like physics and engineering.
Understanding how to manipulate algebraic expressions using rules like the Binomial Theorem is important because:
- It enables simplification of complex expressions.
- It helps in solving equations that involve polynomial terms.
Working with algebraic expressions emphasizes translating between different forms – from a simple binomial to an expanded polynomial. This skill is particularly useful in higher mathematics, logical reasoning, and problem-solving in real-world applications like physics and engineering.