Chapter 11: Problem 13
Expand each power. $$ (r+s)^{8} $$
Short Answer
Expert verified
\((r+s)^8 = r^8 + 8r^7s + 28r^6s^2 + 56r^5s^3 + 70r^4s^4 + 56r^3s^5 + 28r^2s^6 + 8rs^7 + s^8\).
Step by step solution
01
Identify the Problem
We need to expand \((r+s)^8\), which means rewriting it as a sum of terms without parentheses using the Binomial Theorem.
02
Apply the Binomial Theorem
The Binomial Theorem states that \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).In this case, replace \(a\) with \(r\), \(b\) with \(s\), and \(n\) with \(8\).
03
Write the General Term
Using the binomial expansion, the general term is \(\binom{8}{k} r^{8-k} s^k\) for \(k = 0, 1, 2, ..., 8\).
04
Calculate Each Term
Calculate each term from \(k = 0\) to \(k = 8\):- For \(k = 0\): \(\binom{8}{0} r^8 s^0 = r^8\)- For \(k = 1\): \(\binom{8}{1} r^7 s^1 = 8r^7 s\)- For \(k = 2\): \(\binom{8}{2} r^6 s^2 = 28r^6 s^2\)- For \(k = 3\): \(\binom{8}{3} r^5 s^3 = 56r^5 s^3\)- For \(k = 4\): \(\binom{8}{4} r^4 s^4 = 70r^4 s^4\)- For \(k = 5\): \(\binom{8}{5} r^3 s^5 = 56r^3 s^5\)- For \(k = 6\): \(\binom{8}{6} r^2 s^6 = 28r^2 s^6\)- For \(k = 7\): \(\binom{8}{7} r^1 s^7 = 8r s^7\)- For \(k = 8\): \(\binom{8}{8} r^0 s^8 = s^8\)
05
Write the Expanded Form
Combine all calculated terms to write the expanded form:\((r+s)^8 = r^8 + 8r^7s + 28r^6s^2 + 56r^5s^3 + 70r^4s^4 + 56r^3s^5 + 28r^2s^6 + 8rs^7 + s^8\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
The binomial expansion is a way to break down expressions of the form \((a + b)^n\) into a sum of terms that do not have parentheses. Here, each term in the expanded form of \((a + b)^n\) is derived using the combination of the formulas and concepts from the Binomial Theorem.
In simpler terms, binomial expansion takes a binomial expression \((a + b)^n\) and expands it into a polynomial, with each term having a specific structure. This is particularly useful when dealing with higher powers, as manually multiplying binomials multiple times can be arduous and time-consuming. The Binomial Theorem provides a clear-cut formula to do this efficiently.
In simpler terms, binomial expansion takes a binomial expression \((a + b)^n\) and expands it into a polynomial, with each term having a specific structure. This is particularly useful when dealing with higher powers, as manually multiplying binomials multiple times can be arduous and time-consuming. The Binomial Theorem provides a clear-cut formula to do this efficiently.
Binomial Coefficients
Binomial coefficients are the numeric factors that appear in the binomial expansion's terms. They are denoted by \(\binom{n}{k}\), which can be read as "n choose k," and are calculated as:\[\binom{n}{k} = \frac{n!}{k!(n-k)!} \]This formula represents the number of ways to choose \(k\) items from \(n\) items without considering the order. These coefficients play a crucial role in determining the magnitude of each term in the binomial expansion.
Let's consider the exercise \((r+s)^8\):
Let's consider the exercise \((r+s)^8\):
- When \(k=0\), \(\binom{8}{0} = 1\)
- When \(k=1\), \(\binom{8}{1} = 8\)
- and so on, up to \(k=8\), \(\binom{8}{8} = 1\)
Polynomial Expansion
Polynomial expansion involves expanding an algebraic expression with multiple terms into a complete polynomial. In the context of the binomial expansion, it transforms a power of a binomial into a sum of terms. Each term in the polynomial is formed by multiplying appropriate powers of the binomial's components and their corresponding binomial coefficients.
For instance, \((r+s)^8\) is expanded into:
For instance, \((r+s)^8\) is expanded into:
- \(r^8 + 8r^7s + 28r^6s^2 + 56r^5s^3 + 70r^4s^4\)
- \(+ 56r^3s^5 + 28r^2s^6 + 8rs^7 + s^8\)