Chapter 10: Problem 5
CELL PHONES A person using a cell phone can be located in respect to three cellular towers. In a coordinate system where a unit represents one mile, the caller is determined to be 50 miles from a tower at the origin, 40 miles from a tower at \((0,30),\) and 13 miles from a tower at \((35,18) .\) Where is the caller?
Short Answer
Step by step solution
Write the equation for each tower
Set equations for Tower 1 (at origin)
Set equations for Tower 2 (at (0, 30))
Set equation for Tower 3 (at (35, 18))
Solve the equations simultaneously
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation Solving
The Distance Formula is described as:\[ \sqrt{(x-x_1)^2 + (y-y_1)^2} = d \] where \((x_1, y_1)\) represents the coordinates of a tower, and \(d\) is the distance from the caller to the tower. The goal is to express this relationship in a way that it can be solved mathematically. By squaring both sides of the equation, you can eliminate the square root, making it easier to handle algebraically:
- For Tower 1, solve: \(x^2 + y^2 = 2500\)
- For Tower 2, solve: \(x^2 + (y-30)^2 = 1600\)
- For Tower 3, solve: \((x-35)^2 + (y-18)^2 = 169\)
Simultaneous Equations
- \(x^2 + y^2 = 2500\)
- \(x^2 + (y-30)^2 = 1600\)
- \((x-35)^2 + (y-18)^2 = 169\)
For instance, in this case:
- Rearrange the second equation to: \(2500 - 60y + 900 = 1600\) which simplifies to \(60y = 1800\) and \(y = 30\).
Geometric Location
Here's the process:
- You're given the distances from the towers and their coordinates.
- Using the Distance Formula, set equations that represent the caller's distance from each tower, creating a system of equations.
- Solve these simultaneous equations to find the coordinates \((x, y)\) where all conditions are satisfied.