Chapter 10: Problem 38
What is the standard form of the equation of the conic given below? \(2 x^{2}-4 y^{2}-8 x-24 y-16=0\) F. \(\frac{(x-4)^{2}}{11}-\frac{(y+3)^{2}}{3}=1\) G. \(\frac{(y-3)^{2}}{3}-\frac{(x-2)^{2}}{6}=1\) H. \(\frac{(y+3)^{2}}{4}-\frac{(x+2)^{2}}{5}=1\) J. \(\frac{(x-4)^{2}}{11}+\frac{(y+3)^{2}}{3}=1\)
Short Answer
Step by step solution
Rearrange and Group Terms
Factor Out Coefficients
Complete the Square for x-Term
Complete the Square for y-Term
Rewrite the Equation with Completed Squares
Simplify and Isolate the Constant
Divide by 4 to Standardize
Match with Provided Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
When completing the square, start with a quadratic expression like \(x^2 + bx\).The goal is to add and subtract the perfect number that will turn \(x^2 + bx\) into a perfect square trinomial. To find this number, take half of the coefficient of x, then square it:
- For x^2 - 4x, half of -4 is -2, and squaring it gives 4.
- For y^2 + 6y, half of 6 is 3, squaring gives 9.
Hyperbola Equation
\[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\] or \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1.\] Here is what each part represents:
- The center of the hyperbola is at \((h, k).\)
- The terms a^2 and b^2 define the distances that shape the hyperbola along x-axis or y-axis respectively.
- The difference in signs between the terms indicates that it is a hyperbola.
Standard Form of Conic Sections
For hyperbolas, which was our focus here, the standard forms are:
- Circular symmetry: \[\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\]
- Reverse symmetry: \[\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1\]
- The direction in which the conic opens (along xy or yx axis).
- Scale: determined by values of a^2 and b^2, which impact the stretching or compression of the conic.