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A hyperbola has foci at \((4,0)\) and \((-4,0) .\) The value of \(a\) is \(1 .\) Write an equation for the hyperbola.

Short Answer

Expert verified
The equation of the hyperbola is \( x^2 - \frac{y^2}{15} = 1 \).

Step by step solution

01

Identify the Center

The center of the hyperbola, given the foci at (4, 0) and (-4, 0), is the midpoint of these foci. The center is at the origin, (0, 0).
02

Determine the Distance Between Foci

Calculate the distance between the foci, which is the distance from (4, 0) to (-4, 0). This distance is 8. Thus, we find that 2c = 8, so c = 4.
03

Use the Relationship Among a, b, and c

Recall the hyperbola relationship: \[ c^2 = a^2 + b^2 \] Substitute the known values (a=1, c=4): \[ 4^2 = 1^2 + b^2 \]\[ 16 = 1 + b^2 \]\[ b^2 = 15 \]
04

Formulate the Standard Equation of the Hyperbola

For a horizontal hyperbola centered at (0, 0), with a=1 and b calculated: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] Substituting the value of a and b gives: \[ \frac{x^2}{1} - \frac{y^2}{15} = 1 \]
05

Write the Final Equation

The standard equation is simplified to: \[ x^2 - \frac{y^2}{15} = 1 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equation of Hyperbola
To understand the equation of a hyperbola, we first need to recognize the standard form. A hyperbola in its simplest form is expressed as \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]when centered at the origin and opening horizontally. Here, \(x^2\) and \(y^2\) indicate the axes of symmetry, where \(a\) and \(b\) are distances that define the hyperbola’s size and shape. The value \(a\) relates to the distance from the center to the vertices, while \(b\) impacts the curvature and distance of the hyperbola's arms. Both parameters ultimately determine the equation's structure by extending or compressing the curves. For vertical hyperbolas, the equation would be:\[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \] In our example, we have \(x^2 - \frac{y^2}{15} = 1\), indicating a horizontal hyperbola because the \(x\) term comes first and is positive. The structure of this equation is crucial for graphing and understanding the hyperbola considerably.
Conic Sections
Conic sections involve slicing a cone in different ways to form unique shapes: circles, ellipses, parabolas, and hyperbolas. Imagine slicing a cone vertically at an angle; the intersecting shape impacts the geometry. - **Circle**: A cross-section parallel to the cone's base forms a circle, noted by an equation like \(x^2 + y^2 = r^2\), where \(r\) is the radius.- **Ellipse**: Slicing at an angle thinner than the base forms an ellipse. It can be expressed as \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\).- **Parabola**: Cutting parallel to the cone’s side produces a parabola, described in simple terms as \(y = ax^2 + bx + c\).- **Hyperbola**: Slicing perpendicular produces two curves facing outward, known as a hyperbola. Its equation takes form based on its orientation, either horizontally or vertically.Hyperbolas are among the most interesting conics due to their open, divergent shape. They embody unique symmetry and are applied in modeling various physical phenomena like satellite dishes and natural sound wave patterns.
Foci of Hyperbola
Foci are key points within hyperbolas that define their shape and orientation. A hyperbola always has two foci, located along its major axis. These points lie outside the hyperbola, at a distance \(c\) from the center. For our problem, the foci are at (4, 0) and (-4, 0), indicating horizontal orientation.The mathematical relationship connecting foci and hyperbolas is given by:\[ c^2 = a^2 + b^2 \]In our example, since \(2c = 8\), we deduce \(c = 4\). Even though the foci sit beyond the vertices, their role is integral. Observing how the difference in distances from points on the hyperbola to each focus remains constant helps us keep track of the structure and alignment. These characteristics illuminate insights into the hyperbola's openness and the distance between its arms. Understanding these aspects helps apply hyperbolas in tracking planetary orbits, engineering optics, and more.

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Most popular questions from this chapter

FOOTBALL When a ball is thrown or kicked, the path it travels is shaped like a parabola. Suppose a football is kicked from ground level, reaches a maximum height of 25 feet, and hits the ground 100 feet from where it was kicked. Assuming that the ball was kicked at the origin, write an equation of the parabola that models the flight of the ball.

For Exercises \(34-37,\) use the following information. A hyperbola with asymptotes that are not perpendicular is called a nonrectangular hyperbola. Most of the hyperbolas you have studied so far are nonrectangular. A rectangular hyperbola is a hyperbola with perpendicular asymptotes. For example, the graph of \(x^{2}-y^{2}=1\) is a rectangular hyperbola. The graphs of equations of the form \(x y=c,\) where \(c\) is a constant, are rectangular hyperbolas with the coordinate axes as their asymptotes. Describe the transformations that can be applied to the graph of \(x y=2\) to obtain the graph of \(x y=-2\) .

REVIEW Given: Two angles are supplementary. One angle is \(25^{\circ}\) more than the measure of the other angle. Conclusion: The measures of the angles are \(65^{\circ}\) and \(90^{\circ} .\) This conclusion \(-\) \(\mathrm{F}\) is contradicted by the first statement given. \(\mathrm{G}\) is verified by the first statement given. H invalidates itself because a \(90^{\circ}\) angle cannot be supplementary to another. J verifies itself because \(90^{\circ}\) is \(25^{\circ}\) more than \(65^{\circ} .\)

A curved mirror is placed in a store for a wide-angle view of the room. The equation \(\frac{x^{2}}{1}-\frac{y^{2}}{3}=1\) models the curvature of the mirror. A small security camera is placed 3 feet from the vertex of the mirror so that a diameter of 2 feet of the mirror is visible. If the back of the room lies on \(x=-18\) , what width of the back of the room is visible to the camera?

Solve each equation. Round to the nearest ten-thousandth. $$ e^{3 x}=4 $$

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