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Chapter 12: Q36. (page 796)

Solve each equation. State any extraneous solutions.

t−3t+3−2tt−3=−1

Short Answer

Expert verified

The solution of the equation is 0.

Step by step solution

01

Step 1. State the concept for observational studies.

The linear equations in one variable is an equation which is expressed in the form of ax+b=0, where a and b are two integers, and x is a variable and has only one solution.

02

Step 2. Solve the equation.

The equation can be solved as follows:

t−3t+3−2tt−3=−1(t−3)(t−3)−2t(t+3)(t−3)(t+3)=−1(t−3)(t−3)−2t(t+3)=−1(t−3)(t+3)t2−3t−3t+9−2t2−6t=−t2+3t−3t+9−t2−12t+9=−t2+9−12t=0t=−012t=0

03

Step 3. Check the solution.

To check the solution, substitute t=0for in the original equation,

t−3t+3−2tt−3=−10−30+3−2(0)0−3=−1−33−0−3=−1−1−0=−1−1=−1LHS=RHS

Since both sides are equal, the equation is correct.

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