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Chapter 12: Q25. (page 745)

The first stage of a rocket burns 28 seconds longer than the second stage. If the total burning time is 152 seconds, how many seconds is the first stage?

Short Answer

Expert verified

The number of seconds in the first stage is 90.

Step by step solution

01

Step 1. State the concept for observational studies.

The linear equations in one variable is an equation which is expressed in the form of ax+b=0, where a and b are two integers, and x is a variable and has only one solution.

02

Step 2. Form the equation.

Let the number of seconds in the second stage bex

The first stage is 28 seconds longer than the second stage.

Therefore, the number of seconds in the first stage inlocalid="1648194538534" x+28seconds.

localid="1648194343973" Totalburningtime=152secondsx+x+28=152

03

Step 3. Solve the equation.

The equation can be solved as follows:

x+x+28=1522x+28=1522x+28鈭�28=152鈭�282x=1242x2=1242x=62

Number of seconds in the first stage =x+28=62+28=90.

Therefore, the number of seconds in the first stage is 90 seconds.

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