91Ó°ÊÓ

Coordinates are $(2,4)$and$(−3,4)$

The distance ($d$) between the points$(x_1,y_1)$ and$(x_2,y_2)$ is given by:

role="math" localid="1648104476512" $d=\sqrt{{\left(x_2−x_1\right)}^2+{\left(y_2−y_1\right)}^2}$

Therefore, the distance ($d$) between the points$(2,4)$ and$(−3,4)$ is:

role="math" localid="1648104501983" $\begin{array}{l}d=\sqrt{{\left(−3−2\right)}^2+{\left(4−4\right)}^2}\\ =\sqrt{{\left(−5\right)}^2+{\left(0\right)}^2}\\ =\sqrt{25+0}\\ =\sqrt{25}\\ =\sqrt{5^2}\\ =5\end{array}$

Therefore, the distance ($d$) between the points$(2,4)$ and$(−3,4)$ is 5.

The midpoint formula states that the midpoint of a line segment with endpoints at$(x_1,y_1)$ and$(x_2,y_2)$ is given by $M=\left(\frac{{\displaystyle x_1+x_2}}{{\displaystyle 2}},\frac{{\displaystyle y_1+y_2}}{{\displaystyle 2}}\right)$.

The midpoint ($M$) of the line segment with endpoints at$(2,4)$ and$(−3,4)$ is given by:

role="math" localid="1648104722106" $\begin{array}{l}M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\\ =\left(\frac{2+(−3)}{2},\frac{4+4}{2}\right)\\ =\left(\frac{2−3}{2},\frac{8}{2}\right)\\ =\left(\frac{−1}{2},4\right)\\ =(−0.5,4)\end{array}$

Therefore, the midpoint of the line segment with the endpoints at$(2,4)$ and$(−3,4)$ is $(−0.5,4)$.