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Find the quotient.

x2+7x+12x2−25÷x2−92x+10

Short Answer

Expert verified

The final answer is 2(x+4)(x−5)(x−3).

Step by step solution

01

Step 1. Define a rational function.

A function of the form y=pq is called a rational function, where p and q are the polynomials and q≠0.

02

Step 2. Define the quotient of two expressions ab and cd.

The quotient of two expressions aband cd, where b≠0and d≠0, is given below.

ab÷cd=ab×dc=acbd â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰...........(1)

03

Step 3. Calculate the quotient x2+7x+12x2−25÷x2−92x+10.

Use (1)to find the quotient x2+7x+12x2−25÷x2−92x+10.

role="math" localid="1648030191290" x2+7x+12x2−25÷x2−92x+10=x2+7x+12x2−25×2x+10x2−9=(x2+7x+12)(2x+10)(x2−25)(x2−9)=(x2+4x+3x+12)2(x+5)(x2−52)(x2−9)=x(x+4)+3(x+4)2(x+5)(x+5)(x−5)(x+3)(x−3)=(x+4)(x+3)(2)(x+5)(x+5)(x−5)(x+3)(x−3)=2(x+4)(x−5)(x−3)

Therefore, the final answer is2(x+4)(x−5)(x−3).

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