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Chapter 11: Q14. (page 728)

A 135-pound person sits 5 feet from the centre of a seesaw. How far from the centre should a 108-pound person sit to balance the seesaw?

Short Answer

Expert verified

To balance the seesaw, a person should sit at6.25feet from the centre.

Step by step solution

01

Step 1. Torque.

Torque is given by 蟿=rF.

02

Step 2. Apply product rule.

Apply product rule for inverse variation.

r1F1=r2F2(5)(135脳32.17)=r2(108脳32.17)

03

Step 3. Simplify.

Simplify the above obtained equation.

21714.753474.36=3474.36r23474.36r2=6.25

Therefore, to balance the seesaw, a person should sit at6.25feet from the centre.

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