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Which of the following is an equation of the line perpendicular to4x−2y=6 and passing through(4,−4)?

Fy=−34x+3

Gy=−34x−1

Hy=−12x−4

Jy=−12x−2

Short Answer

Expert verified

The equation of the line perpendicular to4x−2y=6 and passing through(4,−4) is

y=−12x−2.

Option Jis correct.

Step by step solution

01

Step 1. State the concept of equation of line in ‘Slope intercept form’.

Suppose ‘m’ is the slope of the a and ‘c’ is the y-intercept of a line , then the equation of the line in slope intercept form is given as,

y=mx+c â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€¦(1).

02

Step 2. State the concept of equation of line in ‘Slope-point form’.

Suppose a line has a slope ‘m’ and passes through the point, then the equation of the line in slope point is given as,

(y−y1)=m(x−x1) â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€¦(2)

03

Step 3. State the concept of ‘perpendicularity of two lines’.

If two lines are pendicular to each other, then the product of their slopes is equal to ‘-1’.

That is, suppose m1is the slope of line one and m2is the slope of line two,

Thenm1(m2)=−1 â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€¦(3)

04

Step 3. Calculate the equation of the line perpendicular to 4x−2y=6 and passing  through (4,−4).

First write the equation 4x−2y=6in slope intercept form and find its slope.

4x−2y=64x−6=2y2y=4x−62y2=4x−62y=4x2−62y=2x−3

On comparing y=2x−3with y=mx+c

The slope of the line y=2x−3is m=2.

Let m1be the slope of the line perpendicular to the line y=2x−3.

m(m1)=−1 â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰[±«²õ¾±²Ô²µâ€‰â¶Ä‰3]2(m1)=−1m1=−12

The line passes through the point (4,−4)and has a slope m1=−12.

Substitute (4,−4)as (x1,y1)and −12as m in (2) and find the required equation.

Therefore, by slope point form

(y−(−4))=−12(x−4)y+4=−12(x)−−12(4)y+4=−12x+42y+4=−12x+2y=−12x+2−4y=−12x−2

Therefore, the required equation y=−12x−2.

Option Jis correct.

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