91Ó°ÊÓ

Coordinates are $\left(−1,−3\right)$and$\left(3,5\right)$

The distance (d) between the points$\left(x_1,y_1\right)$ and$\left(x_2,y_2\right)$ is given by:

$d=\sqrt{{\left(x_2−x_1\right)}^2+{\left(y_2−y_1\right)}^2}$

Therefore, the distance (d) between the points$\left(−1,−3\right)$ and$\left(3,5\right)$ is:

width="328" height="268" role="math">d=3−−12+5−−32=3+12+5+32=42+82=16+64=80=16×5=45=42.236068=8.944272≈8.94roundedtothenearesthundredth

Therefore, the distance (d) between the points$\left(−1,−3\right)$ and$\left(3,5\right)$ is $8.94$.

The midpoint formula states that the midpoint M of a line segment with endpoints at$\left(x_1,y_1\right)$ and$\left(x_2,y_2\right)$ is given by $M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$.

The midpoint (M) of the line segment with endpoints at$\left(−1,−3\right)$ and$\left(3,5\right)$ is given by:

$$\begin{gathered} M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right) \\ =\left(\frac{−1+3}{2},\frac{−3+5}{2}\right) \\ =\left(\frac{2}{2},\frac{2}{2}\right) \\ =\left(1,1\right) \end{gathered}$$

Therefore, the midpoint of the line segment with the endpoints at$\left(−1,−3\right)$ and$\left(3,5\right)$ is $\left(1,1\right)$.