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Algebra 1

Carter, Cuevas, Day, Holiday, Luchin

$Math Studyset 91影视 Explanations$ Math

Student Edition 路 801 pages

ISBN: 9780078884801

Chapter 10: Q37. (page 658)

Solve each equation. Check your solution.
$10 + 2 \sqrt{x} = 0$

Short Answer

Expert verified

There is no solution of the given equation.

Check:

Substitute 25 for x in the given equation $10 + 2 \sqrt{x} = 0$ .

$10 + 2 \sqrt{x} = 0 10 + 2 \sqrt{25} \underset{炉}{\underset{炉}{?}} 0 10+2 (5) \underset{炉}{\underset{炉}{?}} 0 10+10 \underset{炉}{\underset{炉}{?}} 0 20 鈮� 0$

Therefore, $x = 25$ is not the solution of the given equation $10 + 2 \sqrt{x} = 0$ .

Step by step solution

01

Step 1. Rewrite the given equation.

The given equation can be written as:

$10 + 2 \sqrt{x} = 0 2 \sqrt{x} = 鈭� 10 \sqrt{x} = 鈭� \frac{10}{2} \sqrt{x} = 鈭� 5$

02

Step 2. Solve the given equation.

The solution of the given equation is:

${(\sqrt{x})}^{2} = {(鈭� 5)}^{2} (squaringbothsides) x = 25$

Therefore, the value of x is 25.

03

Step 3. Check the solution.

Substitute 25 for x in the given equation $10 + 2 \sqrt{x} = 0$ .

$10 + 2 \sqrt{x} = 0 10 + 2 \sqrt{25} \underset{炉}{\underset{炉}{?}} 0 10+2 (5) \underset{炉}{\underset{炉}{?}} 0 10+10 \underset{炉}{\underset{炉}{?}} 0 20 鈮� 0$

Therefore, $x = 25$ is not the solution of the given equation $10 + 2 \sqrt{x} = 0$ .

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