91Ó°ÊÓ

When the square root of a term is squared, then the resulting value will be the term which is inside the root. That is,

${\left(\sqrt{a}\right)}^2=a$

Solve the equation$\sqrt{10x}=20$ to get the value of ‘x’.

$\sqrt{10x}=20$

Squaring both the sides

$$\begin{gathered} {\left(\sqrt{10x}\right)}^2={\left(20\right)}^2 \\ 10x=400\text{ â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰}\left[\text{±«²õ¾±²Ô²µâ€‰â¶Ä‰}{\left(\sqrt{a}\right)}^2=a\right] \\ \frac{10x}{10}=\frac{400}{10} \\ x=40 \end{gathered}$$

Substitute$x=40$ in the left hand side (L.H.S) of the equation $\sqrt{10x}=20$to verify whether the value satisfies the equation or not.

$$\begin{gathered} \text{L.H.S}=\sqrt{10x} \\ =\sqrt{10\left(40\right)} \\ =\sqrt{400} \\ =20 \\ =\text{R.H.S â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â€‰}\left[\text{¸é.±á.³§=¸é¾±²µ³ó³Ù​â¶Ä‹â¶Ä‰â¶Ä‰h²¹²Ô»å â¶Ä‰s¾±»å±ð}\right] \end{gathered}$$

L.H.S=R.H.S

Thus,$x=40$satisfies the given equation.

Hence verified.