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Simplify12a2b2−4b223

Short Answer

Expert verified

The simplified version of12a2b2−4b223 is 32a6b10.

Step by step solution

01

Step 1. State the ‘Law of indices’ for power of index numbers.

If a term with a power is itself raised to a power, then the powers are multiplied together.

In general:xmn=xm×n

02

Step 2. State the multiplication rule of ‘laws of indices’.

If the two terms having the same base are multiplied together, then their indices are added.

In general:xm×xn=xm+n

03

Step 3. State the product power law of ‘laws of indices’. 

According to this lawwhen a product is raised to a power, every factor of the product is raised to the power.

In general:xym=xmym

04

State the division rule of ‘laws of indices’.

If a fraction is raised to a power, then every terms of the fraction is raised to the power.

In general:xym=xmym

05

Step 5. Simplify the expression.

The given expression is:12a2b2−4b223 

Apply the laws of indices and simplify the above expression.

12a2b2−4b223=123a23b23−4b22=1323a2×3b2×3−4b2×2=18a6b6−4b4=18a6b6−44b4=18a6b6256b4

Collect the like terms together and simplify further.

12a2b2−4b223=18×256a6b6×b4=32a6b6+4=32a6b10

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