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Subtract the polynomials below.

7a2+6a−2−−4a3+3a2+5

  1. 4a3+4a2+6a−7
  2. 11a2+3a−7
  3. 4a3+10a2+6a+3
  4. 4a3+7a3−3a

Short Answer

Expert verified

The result obtained after the subtraction of the given polynomials is 4a3+4a2+6a−7. Therefore, the option A is correct.

Step by step solution

01

Step 1. Define the additive inverse.

The additive inverse of a number ‘a’ is-a as a+−a=0.

02

Step 2. Find the result obtained after the subtraction of the given polynomials.

The difference of the polynomials 7a2+6a−2and −4a3+3a2+5can be find out by adding the polynomial 7a2+6a−2and additive inverse of the polynomial −4a3+3a2+5.

The additive inverse of the polynomial−4a3+3a2+5 is:

role="math" localid="1647689278588" 4a3−3a2−5

Therefore, it can be noticed that:

role="math" localid="1647689455168" 7a2+6a−2−−4a3+3a2+5=7a2+6a−2+4a3−3a2−5=7a2+6a−2+4a3−3a2−5=4a3+7a2−3a2+6a−2−5=4a3+4a2+6a−7

Therefore, the result obtained after the subtraction of the given polynomials is 4a3+4a2+6a−7. Therefore, the option A is correct.

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