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Express the perimeter of the rectangle below polynomial.

F3x2−4x+7

G3x2+x+7

H6x2−8x+14

J6x2−4x+7

Short Answer

Expert verified

The perimeter of the given rectangle is 6x2−8x+14. Therefore, the option H is correct.

Step by step solution

01

Step 1. Write the formula for the perimeter of the rectangle.

The perimeter Pof the rectangle is given by:

P=2L+B

WhereL andB are the length and breadth of the rectangle respectively.

02

Step 2. Express the perimeter of the given rectangle in polynomial.

The given diagram of the rectangle is:

From the given diagram of the rectangle, it can be noticed that the length and breadth of the triangle are2x2−x+3 andx2−3x+4 respectively.

Therefore, the values ofL andB are2x2−x+3 andx2−3x+4 respectively.

Substitute the values ofL andB in the formula of the perimeter of the rectangle.

Therefore, it is obtained that:

P=2L+B=22x2−x+3+x2−3x+4=22x2+x2−x−3x+3+4=23x2−4x+7=6x2−8x+14

Therefore, the perimeter of the given rectangle in polynomial is 6x2−8x+14. Therefore, the option H is correct.

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