91Ó°ÊÓ

The solution of the given compound inequality$m−3<6$ and$m+2>4$ is:

Solve the inequality $m−3<6$.

$$\begin{gathered} m−3<6 \\ m−3+3<6+3 \\ m<9 \\ m∈\left(−\mathrm{∞},9\right) \end{gathered}$$

Solve the inequality $m+2>4$.

$$\begin{gathered} m+2>4 \\ m+2−2>4−2 \\ m>2 \\ m∈\left(2,\mathrm{∞}\right) \end{gathered}$$

A compound inequality containing ‘and’ is true if both inequalities are true.

That implies the solution of the compound inequality containing ‘and’ is the intersection of the solutions of the two simple statements.

Find the intersection of the solutions of the inequalities$m−3<6$ and$m+2>4$ to find the solution of the compound inequality$m−3<6$ and $m+2>4$.

The intersection of the solutions of the inequalities$m−3<6$ and$m+2>4$ is:

$m∈\left(2,9\right)$

Therefore, the solution of the compound inequality$m−3<6$ and$m+2>4$ is $m∈\left(2,9\right)$.

The graph of the solution set which is$m∈\left(2,9\right)$ is: