91Ó°ÊÓ

The standard form of slope and intercept form of the straight line is $y=mx+c$.

Here, $m$is the slope of the straight line and $c$is the $y$-intercept of the equation.

Also, when both the intercepts are given, use the intercept form of a straight line given below,

$\frac{x}{a}+\frac{y}{b}=1$, where $a$is the $x$-intercept and b is the $y$-intercept.

The equation of the line $y=\frac{1}{3}x−2$can be written as

$$\begin{gathered} y=\frac{1}{3}x−2 \\ \frac{1}{3}x−y=2 \\ \frac{x}{6}−\frac{y}{2}=1\left[\text{Divideeachtermbyconstantterm}\right] \\ \frac{x}{6}+\frac{y}{\left(−2\right)}=1 \end{gathered}$$

This form of the equation shows the $x$-and and $y$-intercepts of the line. The line meets the $x$-axis at the point$\left(6,0\right)$ and the $y$-axis at the point $\left(0,−2\right)$.

Join these two points and get the plot of the equation of a line.

Mark the points $\left(6,0\right)$and $\left(0,−2\right)$on a graph and join the two points to form the required line.