91Ó°ÊÓ

The standard form associated with the slope and the intercept form related to the line that is straight$y=mx+c$ in which the slope is represented by $m$ and the $y$-intercept is represented by $c$ can be used to write the required equation.

Determine the depreciation associated with the car for each year.

$$\begin{gathered} \frac{28500−23700}{3}=\frac{4800}{3} \\ =1600 \end{gathered}$$

Take the help of obtained standard form represented by $y=mx+c$in which the required values can be filled by using the obtained depreciation, the initial price of the car, $t$which represents the time in years and $C$which will represent the cost.

$C=2850+1600t$

The obtained equation is $C=2850+1600t$so the required value can be determined by using the gap of years between 2005 and 2012 in place of time into the obtained equation so,

$$\begin{gathered} C=28500−1600×7 \\ =17300 \end{gathered}$$

The obtained value is the same as in option A.