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91Ó°ÊÓ

Evaluate 3a2−2ab+cfor the values given.

a=2,b=1,c=5

Short Answer

Expert verified

The value of the expression is13.

Step by step solution

01

Step 1. State the concept used.

  • To get rid of a number in addition from one side, subtract the same number from both sides of the equal sign.
  • To get rid of a number in subtraction from one side, add the same number on both sides of the equal sign.
  • To get rid of a number in multiplication from one side, divide the same number from both sides of the equal sign.
  • To get rid of a number in the division from one side, multiply the same number on both sides of the equal sign.

Rules of Addition/ Subtraction:

  • Two numbers with similar signs always get added and the resulting number will carry the similar sign.
  • Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of the larger number.

Rules of Multiplication/ Division:

  • The product/quotient of two similarsign numbers is always positive.
  • The product/quotient of two numbers with opposite signs is always negative.
02

Step 2. Substitute the values. 

In order to calculate 3a2−2ab+c, substitute 2 for a,1for b, and 5 for c.

3a2−2ab+c=322−221+5

03

Step 3. Simplify the expression.

Further, simplify the expression by applying the rules of BODMAS.

3a2−2ab+c=322−221+5

=3×4−4+5=12−4+5=8+5=13

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