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The given equation is 鈥�$5h鈭�7=5\left(h鈭�2\right)+3$鈥�.

Solving,

$5h鈭�7=5\left(h鈭�2\right)+3$ (Given equation)

$5h鈭�7=5h鈭�10+3$ (Distributive property)

$5h鈭�7=5h鈭�7$ (Simplify)

The expressions on both sides are identical.

This implies that the given equation is an identity. So, it is true for all values of h.

Put $h=1$in the given equation $5h鈭�7=5\left(h鈭�2\right)+3$to get,

$\begin{array}{l}5鈭�7=5\left(1鈭�2\right)+3\\ 鈭�2=5\left(鈭�1\right)+3\\ 鈭�2=鈭�5+3\\ 鈭�2=鈭�2\end{array}$

Since the values on the left-hand side and the right-hand side are equal, it can be said that $h=1$is a solution of the given equation.

Put $h=0$in the given equation $5h鈭�7=5\left(h鈭�2\right)+3$to get,

$\begin{array}{l}5\left(0\right)鈭�7=5\left(0鈭�2\right)+3\\ 0鈭�7=5\left(鈭�2\right)+3\\ 鈭�7=鈭�10+3\\ 鈭�7=鈭�7\end{array}$

Since the values on the left-hand side and the right-hand side are equal, it can be said that $h=0$is a solution of the given equation.

Thus, it can be seen that a linear equation has at least two different solutions. This verifies that the given equation is an identity.