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The given equation is 鈥�$14v+6=2\left(5+7v\right)鈭�4$鈥�.

Solving,

$14v+6=2\left(5+7v\right)鈭�4$ (Given equation)

$14v+6=10+14v鈭�4$ (Distributive property)

$14v+6=14v+6$ (Simplify)

The expressions on both sides are identical.

This implies that the given equation is an identity. So, it is true for all values of v.

Put $v=1$in the given equation $14v+6=2\left(5+7v\right)鈭�4$to get,

$\begin{array}{l}14+6=2\left(5+7\right)鈭�4\\ 20=2\left(12\right)鈭�4\\ 20=24鈭�4\\ 20=20\end{array}$

Since the values on the left-hand side and the right-hand side are equal, it can be said that $v=1$is a solution of the given equation.

Put $v=0$in the given equation $14v+6=2\left(5+7v\right)鈭�4$to get,

$\begin{array}{l}14\left(0\right)+6=2\left(5+7\left(0\right)\right)鈭�4\\ 0+6=2\left(5+0\right)鈭�4\\ 6=2\left(5\right)鈭�4\\ 6=10鈭�4\\ 6=6\end{array}$

Since the values on the left-hand side and the right-hand side are equal, it can be said that $v=0$is a solution of the given equation.

Thus, it can be seen that a linear equation has at least two different solutions. This verifies that the given equation is an identity.