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Solve each equation. (Lesson 2-5)

2p−3=17

Short Answer

Expert verified

The solution set will be p=−7andp=10.

Step by step solution

01

Step 1. Use the definition of the absolute value function.

The absolute value or modulus of a real number x denoted |x| is the non-negative value of x without regard to its sign.

Absolute value refers to a point's distance from zero or origin on the number line, regardless of the direction.

02

Step 2. Solve for the first possible solution.

We are given the expressions:|2p−3|=17

Since an absolute function value can never be negative we have two scenarios that are possible.

Case: 1 when expression inside the modulus sign is negative, that is

role="math" localid="1642664720960" −(2p−3)=17 [¶Ù¾±²õ³Ù°ù¾±²ú³Ü³Ù±ð±Õ−2p+3=17−2p+3−3=17−3[Add-3tobothsides]−2p=14−2p×−1=14×−1[multiplyby-1bothsides]

2p=−14p=−142p=−7

03

Step 3. Solve for a second possible solution.

We are given the expressions: |2p−3|=17

Case: 2 when expression inside the modulus sign is positive, that is

role="math" localid="1642664857683" 2p−3=172p−3+3=17+3[Add3tobothsides]2p=20p=202p=10

Hence, the solution set will be p=−7andp=10.

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