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CHEERLEADING For the competition, the cheerleading team is preparing a dance routine that must last 4 minutes, with a variation of 卤5 seconds.

a. Find the least and greatest possible times for the routine in minutes and seconds.

b. Find the least and greatest possible times in seconds.

Short Answer

Expert verified

a. The least possible time for the routine will be 3 minutes 55 seconds and the greatest possible time for the routine will be 4 minutes 5 seconds.

b. The least possible time for the routine in seconds will be 235 seconds and the greatest possible time for the routine in seconds will be 245 seconds.

Step by step solution

01

Part a. Step 1. Write down the given statement.

It is given thatthe dance routine must last 4 minutes.

The variation allowed is5seconds.

02

Part a. Step 2. Evaluate the least and greatest possible time.

Let the time allowed for the dance routine be x.

Therefore,

x=4尘颈苍耻迟别蝉卤5蝉别肠辞苍诲蝉x=4min-5secorx=4min+5secx=3minutes55secondsorx=4minutesand5seconds

03

Part a. Step 3. The conclusion from the least and greatest possible time.

The least possible time for the routine will be 3 minutes 55 seconds.

The greatest possible time for the routine will be 4 minutes 5 seconds.

04

Part b. Step 1. Write down the given statement.

It is given that thedance routine must last 4 minutes.

The variation allowed is5seconds.

05

Part b. Step 2. Evaluate the least and greatest possible time.

Let the time allowed for the dance routine be x. Therefore,

x=4尘颈苍耻迟别蝉卤5蝉别肠辞苍诲蝉x=4min-5secorx=4min+5secx=3minutes55secondsorx=4minutesand5secondsx=360+55secondsorx=460+5secondsx=180+55secondsorx=240+5secondsx=235secondsorx=245seconds

06

Part b. Step 3. The conclusion from the least and greatest possible time.

The least possible time for the routine in seconds will be 235 seconds.

The greatest possible time for the routine in seconds will be 245 seconds.

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