91Ó°ÊÓ

Find the factorization of $24am$ and $9an$.

$$\begin{gathered} 24am=2â‹\dots 2â‹\dots 2â‹\dots 3â‹\dots aâ‹\dots m \\ 9an=3â‹\dots 3â‹\dots aâ‹\dots n \end{gathered}$$

From the factorization of $24am$and $9an$, it can be noticed that the greatest common factor of $24am$and $9an$is $3a$.

Therefore, the greatest common factor of $24am$and $9an$is $3a$.

Find the factorization of $40bm$ and $15bn$.

$$\begin{gathered} 40bm=2â‹\dots 2â‹\dots 2â‹\dots 5â‹\dots bâ‹\dots m \\ 15bn=3â‹\dots 5â‹\dots bâ‹\dots n \end{gathered}$$

From the factorization of $40bm$and $15bn$, it can be noticed that the greatest common factor of $40bm$and $15bn$is $5b$.

Therefore, the greatest common factor of $40bm$and $15bn$is $5b$.

Therefore, it is obtained that:

$24am−9an+40bm−15bn=3a\left(8m\right)−3a\left(3n\right)+5b\left(8m\right)−5b\left(3n\right)$

The distributive property states that:

$ab+ac=a\left(b+c\right)$

Now, use the distributive property to factor out the greatest common factor.

Therefore, it is obtained that:

$24am−9an+40bm−15bn=3a\left(8m\right)−3a\left(3n\right)+5b\left(8m\right)−5b\left(3n\right)$

$$\begin{gathered} =3a\left(8m−3n\right)+5b\left(8m−3n\right) \\ =\left(8m−3n\right)\left(3a+5b\right)\left(\text{takeout}8m-3n\text{ascommonfactor}\right) \end{gathered}$$

Therefore, the factorization of the given polynomial is $\left(8m−3n\right)\left(3a+5b\right)$.