Q22. Factor each polynomial.x2+4x鈭�2... [FREE SOLUTION]

91影视

Algebra 1

Carter, Cuevas, Day, Holiday, Luchin

$Math Studyset 91影视 Explanations$ Math

Student Edition 路 801 pages

ISBN: 9780078884801

Chapter 8: Q22. (page 492)

Factor each polynomial.
$x^{2} + 4 x 鈭� 21$

Short Answer

Expert verified

The factors of the given polynomial are $(x + 3) (x 鈭� 7)$ .

Step by step solution

Step 1. Compare.

Compare a given trinomial to $a x^{2} + b x + c$ and write the values of $a, b$ and $c$ .

$a = 1 b = 4 c = 鈭� 21$

Step 2. List the factors.

List the factors of $- 21$ , where one factor of each pair is negative. Look for the pair of factors with a sum of 4.

Factors of $- 21$	Sum of factors
$1, 鈭� 21$	$鈭� 20$
$鈭� 3, 7$	4

Therefore, correct factors are $- 3$ and 7.

Step 3. Apply factoring pattern of ax2+bx+c.

There are two numbers having a product of $- 21$ and the sum of 4. The numbers are $- 3$ and 7.

$x^{2} + 4 x 鈭� 21 = (x + m) (x + p) = (x 鈭� 3) (x + 7)$

Therefore, the factors of $x^{2} + 4 x 鈭� 21$ are $(x 鈭� 3) (x + 7)$ .

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91影视

Factor each polynomial.
$x^{2} + 4 x 鈭� 21$

Short Answer

Step by step solution

Step 1. Compare.

Step 2. List the factors.

Step 3. Apply factoring pattern of ax2+bx+c.

One App. One Place for Learning.

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91影视

Factor each polynomial.x2+4x鈭�21

Short Answer

Step by step solution

Step 1. Compare.

Step 2. List the factors.

Step 3. Apply factoring pattern of ax2+bx+c.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Statistics

Decision Maths

Mechanics Maths

Geometry

Applied Mathematics

Calculus

Study anywhere. Anytime. Across all devices.

Factor each polynomial.
$x^{2} + 4 x 鈭� 21$