91Ó°ÊÓ

According to the BODMAS rule of simplification, at first, the bracket operation must be completed followed division, by multiplication, addition, and finally subtraction.

The expression $5b−\frac{2a}{c}$where $a=3,\text{ â¶Ä‰}b=4,\text{ }c=2$can be written as

$\begin{array}{l}5b−\frac{2a}{c}=5\left(4\right)−\frac{2\left(3\right)}{2}\\ \text{ â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰}=(5×4)−\frac{(2×3)}{2}\\ \text{ â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰}=20−3\\ \text{ â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰}=17\end{array}$

Substituting $a=8,b=4\text{andc}=16$in $\frac{3ab+c^2}{a}$

$\frac{3ab+c^2}{a}=\frac{3â‹\dots 8â‹\dots 4+{16}^2}{8}$

$\begin{array}{l}{\text{Evaluatethepower16}}^2\\ \frac{3ab+c^2}{a}=\frac{3â‹\dots 8â‹\dots 4+256}{8}\end{array}$

$\begin{array}{l}\text{²Ñ³Ü±ô³Ù¾±±è±ô²â3, 4 \&²¹³¾±è;8¾±²Ô³Ù³ó±ð²Ô³Ü³¾±ð°ù²¹³Ù´Ç°ù}\\ \frac{3ab+c^2}{a}=\frac{96+256}{8}\end{array}$

$\begin{array}{l}\text{´¡»å»å96 \&²¹³¾±è;256¾±²Ô³Ù³ó±ð²Ô³Ü³¾±ð°ù²¹³Ù´Ç°ù}\\ \frac{3ab+c^2}{a}=\frac{352}{8}\end{array}$

$\begin{array}{l}\text{Simplify}\\ \frac{3ab+c^2}{a}=44\end{array}$