91Ó°ÊÓ

Note that a polygon with more than 2 right angles is either a square or a rectangle.

Among the given polygons there are 2 polygons that are either a square or a rectangle, i.e. have more than 2 right angles.

The probability of an event is given by the following formula:

$\mathrm{Probability}\mathrm{of}\mathrm{an}\mathrm{outcome}=\frac{\mathrm{number}\mathrm{of}\mathrm{favorite}\mathrm{outcome}}{\mathrm{total}\mathrm{outcome}}$

The total number of figures is 6.

The number of favorite outcomes is 2 since there are four figures that are not quadrilaterals among the given figures.

Substitute the value of the number of favorite outcomes and total outcomes in the formula for probability.

$$\begin{gathered} \mathrm{P}\left(\mathrm{More}\mathrm{that}2\mathrm{right}\mathrm{angles}\right)=\frac{\mathrm{number}\mathrm{of}\mathrm{favorite}\mathrm{outcome}}{\mathrm{total}\mathrm{outcome}} \\ =\frac{2}{6} \\ =\frac{1}{3} \end{gathered}$$

Hence, the probability of getting a polygon that has more than 2 right angles is $\frac{1}{3}$.