Chapter 7: Problem 44
Write the equation in slope-intercept form. Then graph the equation. $$ 3 x+y=-5 $$
Short Answer
Expert verified
The equation in slope-intercept form is \( y = -3x - 5 \). The graph of the equation starts at the y-intercept (0,-5), moves down 3 units and over 1 unit to the right to place the next point, and continues this pattern to produce a line.
Step by step solution
01
Rewrite into slope-intercept form
The given equation is \(3x + y = -5\). We need to get the equation into the form \(y = mx + b\). So, let's subtract \(3x\) from both sides of the equation to solve for \(y\). This will give us \(y = -3x - 5\). Here, \(m = -3\) is the slope and \(b = -5 \) is the y-intercept.
02
Plot the y-intercept
Start by plotting the y-intercept. The y-intercept given by \(b = -5\) is a point on the y-axis where x = 0. Thus, our first point will be (0,-5).
03
Use the slope to find next points
The slope of a line is the rise over the run, meaning how many units up or down for how many units over. Our slope is -3, which can be rewritten as -3/1, meaning we go down 3 and over 1. Starting from the y-intercept point (0,-5), move down 3 units and then one unit to the right. This will be our second point.
04
Draw the line
Once the two points are plotted, a straight line can be drawn through them. This line represents the equation of the function \(y=-3x-5\). All points on this line satisfy the given equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Linear Equations
Graphing a linear equation involves creating a visual representation of the equation on a coordinate plane. This process provides insight into the relationship between the variables in the equation. The slope-intercept form of a linear equation is particularly convenient for this purpose, as it is expressed as \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
To graph the linear equation \(3x + y = -5\), we first converted it to slope-intercept form, yielding \(y = -3x - 5\). This format tells us that the line crosses the y-axis at -5 and slopes downwards as it moves from left to right. The slope \(m = -3\) indicates a steep incline, as for every step to the right (positive x-direction), the y-value decreases by 3 units.
To graph the linear equation \(3x + y = -5\), we first converted it to slope-intercept form, yielding \(y = -3x - 5\). This format tells us that the line crosses the y-axis at -5 and slopes downwards as it moves from left to right. The slope \(m = -3\) indicates a steep incline, as for every step to the right (positive x-direction), the y-value decreases by 3 units.
Step-by-Step Illustration
The initial step is to plot the y-intercept, (0, -5), on the graph. Next, we use the slope to determine another point on the line. By moving down 3 units and 1 unit to the right from the y-intercept, we find the second point, (1, -8). With at least two points identifiable on the coordinate plane, we can then draw the line that represents the solution to the equation.Finding Slope and Y-Intercept
The slope and y-intercept are fundamental components of a linear equation, which are easily identifiable in slope-intercept form. The slope, represented by \(m\) in the equation \(y = mx + b\), indicates the rate at which y-values change relative to x-values. A positive slope means that as x increases, y also increases, while a negative slope, as in our equation \(y = -3x - 5\), suggests that y decreases as x increases.
The y-intercept \(b\) is the point where the line intersects the y-axis, which occurs when \(x = 0\). In our equation, the y-intercept is -5, which means the line crosses the y-axis below the origin, at point (0, -5).
The y-intercept \(b\) is the point where the line intersects the y-axis, which occurs when \(x = 0\). In our equation, the y-intercept is -5, which means the line crosses the y-axis below the origin, at point (0, -5).
Understanding Slope-Intercept Form
Slope-intercept form is immensely helpful as it tells us at first glance the steepness and the starting point of the line on the graph. To derive the slope and y-intercept from a standard form equation like \(3x + y = -5\), isolate the term \(y\) on one side. This process involves moving the \(x\)-term to the other side of the equation by subtracting it from both sides. Once simplified to slope-intercept form, the slope and y-intercept are immediately apparent, making it possible to sketch the graph of the line efficiently.Plotting Points on a Graph
Once the slope-intercept form has given us a slope and a y-intercept, these two pieces of information can determine enough points to graph the line. Plotting points is a matter of choosing an initial point—commonly the y-intercept—and then using the slope to find additional points.
For the equation \(y = -3x - 5\), we plotted the y-intercept at (0, -5). To find subsequent points, we use the slope of -3, which could be thought of as a 'movement instruction'; it tells us to 'move down 3, then move right 1' starting from (0, -5). This movement gives us a second point, which is crucial for ensuring our line's accuracy.
For the equation \(y = -3x - 5\), we plotted the y-intercept at (0, -5). To find subsequent points, we use the slope of -3, which could be thought of as a 'movement instruction'; it tells us to 'move down 3, then move right 1' starting from (0, -5). This movement gives us a second point, which is crucial for ensuring our line's accuracy.