Chapter 12: Problem 29
Solve the equation. Check for extraneous solutions. $$\sqrt{-x}-\frac{3}{2}=\frac{3}{2}$$
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Chapter 12: Problem 29
Solve the equation. Check for extraneous solutions. $$\sqrt{-x}-\frac{3}{2}=\frac{3}{2}$$
These are the key concepts you need to understand to accurately answer the question.
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Find the midpoint between the two points \((0,0),(0,8)\)
Multiply. $$(6 y-4)(6 y+4)$$
Use the proportion \(\frac{a}{b}=\frac{b}{d},\) where \(a\) \(\boldsymbol{b},\) and \(\boldsymbol{d}\) are positive numbers. Two numbers have a geometric mean of 4. One number is 6 more than the other. a. Use the proportion in Exercise \(73 .\) Rewrite the proportion substituting the given value for the geometric mean. b. Let \(x\) represent one of the numbers. How can you represent "one number is 6 more than the other" in the proportion? Rewrite the proportion using \(x\) c. Solve the proportion in part (b) to find the numbers.
Solve the equation. Check for extraneous solutions. $$x=\sqrt{\frac{3}{2} x+\frac{5}{2}}$$
Find the midpoint between the two points \((-3,3),(2,-2)\)
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