Chapter 12: Problem 19
Solve the equation. Check for extraneous solutions. $$\sqrt{x}-15=0$$
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Chapter 12: Problem 19
Solve the equation. Check for extraneous solutions. $$\sqrt{x}-15=0$$
These are the key concepts you need to understand to accurately answer the question.
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Use the proportion \(\frac{a}{b}=\frac{b}{d},\) where \(a\) \(\boldsymbol{b},\) and \(\boldsymbol{d}\) are positive numbers. Two numbers have a geometric mean of 4. One number is 6 more than the other. a. Use the proportion in Exercise \(73 .\) Rewrite the proportion substituting the given value for the geometric mean. b. Let \(x\) represent one of the numbers. How can you represent "one number is 6 more than the other" in the proportion? Rewrite the proportion using \(x\) c. Solve the proportion in part (b) to find the numbers.
Find the midpoint between the two points \((0,-3),(-4,2)\)
Multiply. $$(2 a-9 b)^{2}$$
Use the following information. You and a friend go hiking. You hike 3 miles north and 2 miles west. Starting from the same point, your friend hikes 4 miles east and 1 mile south. If you and your friend want to meet for lunch, where could you meet so that both of you hike the same distance? How far do you have to hike?
For what values of the variable is the rational expression undefined? $$\frac{5}{x-4}$$
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